Jim have a dollar in 20 cent in his pocket and takes out a dollar how much he have left in his pocket answer- 20 cent
Step 
<u>Find the slope of the given line</u>
Let

slope mAB is equal to

Step 
<u>Find the slope of the line that is perpendicular to the given line</u>
Let
CD ------> the line that is perpendicular to the given line
we know that
If two lines are perpendicular, then the product of their slopes is equal to 
so

Step 
<u>Find the equation of the line with mCD and the point (3,0)</u>
we know that
the equation of the line in the form point-slope is equal to

Multiply by
both sides


therefore
the answer is
the equation of the line that is perpendicular to the given line is the equation 
The answer is B) add 1.25 and 2.70 and subtract that from 10.00
Calculate the number of people who sat on the visitors' side:
8644
-5100
--------
3544
Now divide 3544 people by 8 sections:
3544 people
----------------- = 443 per section.
8 sections
a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as
... c = k·s² + m·s + n
Filling in the given values gives three equations in k, m, and n.

Subtracting each equation from the one after gives

Subtracting the first of these equations from the second gives

Using the next previous equation, we can find m.

Then from the first equation
[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]
There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with
... c = 0.01s² - s + 37
b) At 150 kph, the cost is predicted to be
... c = 0.01·150² -150 +37 = 112 . . . cents/km
c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.
d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.