Question

Find an equation of the line that passes through the points (-0.5,0.75) and (0.75,-0.5)

Answer 1

The equation of the line can be shown using the slope intercept form that is

y= mx+b

where m is the slope and b is the y intercept

So firstly we have to find the value of slope m

To find the value of slope m we apply the formula

$m= \frac{( y_{2} - y_{1})}{( x_{2} - x_{1})}$

So we can plug the values using the two given points

(-0.5,0.75) and (0.75,-0.5)

$m= \frac{(-0.5-0.75) }{(0.75-(-0.5))} = \frac{-1.25}{1.25} = -1$

So m = -1

Plug m=-1 in the equation we get

y= -1x +b

Now we have to find the value of b

to find the value of b , we plug any one pint in the equation

0.75 = -1(-0.5) +b

0.75 = 0.5 +b

Subtract 0.5 from both sides

0.25 = b

or

b= 0.25

Now plug the value of b , in the equation

we get

y = -1x +0.25

hence the equation of the line is y = -1x +0.25