Question

Emil's backpack weighs LaTeX: 6\frac{3}{8}6 3 8pounds. He removes a book that weighs LaTeX: \frac{3}{4}3 4 pound. Then he removes a book that weighs LaTeX: \frac{1}{2}1 2 pound. How much does Emil's backpack weigh now

Answer 1

Answer:

Emil's backpack weighs  $7\frac{5}{8}$ pounds

Step-by-step explanation:

Given:

Weight of Emil's backpack=$6\frac{3}{8}$

Weight of book 1 =$\frac{3}{4}$

Weight of book 2 =$\frac{1}{2}$

To Find:

The weight of Emil's backpack after books are removed=?

Solution:

weight of Emil's backpack after books are removed= Weight of backpack -Weight of book 1- Weight of book 2

Substituting the values,

weight of Emil's backpack after books are removed=$6\frac{3}{8}-\frac{3}{4}-\frac{1}{2}$

=>$\frac{51}{8}-\frac{3}{4}-\frac{1}{2}$ (converting mixed fraction into normal fraction}

Taking LCM for the denominators

8= 2 x 2 x 2

4= 2 x 2

2= 2 x 1

Least Common Multiple(8,4,2) = 2 x 2 x 2

Least Common Multiple(8,4,2) = 8

so

=>$\frac{51}{8}+\frac{6}{8}+\frac{4}{8}$

=>$\frac{51+6+4}{8}$

=>$\frac{61}{8}$

=>$7\frac{5}{8}$