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laila [671]
3 years ago
8

$300 at 5% annual interest for 7 years.

Mathematics
2 answers:
Tamiku [17]3 years ago
7 0
The answer is "3. $420.00"
e-lub [12.9K]3 years ago
6 0
It's the last one!

Hope this helps!
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A seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus. How many yards will she need to make costume
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Answer:

100 yards of fabric

Step-by-step explanation:

12 divided by 3 = 4 yards of fabric per costume

4 x 25 = 100 yards of fabric

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The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi
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Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

(b) 0.7910

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Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

The random variable <em>X</em> is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

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3 years ago
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is 0.2222....

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Step-by-step explanation:

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This is wanting you to find the average. So add up the services and divide them by the number of services. The answer is Allcante Royal Hotel, which has a mean of 8. The other one has a mean of 7
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