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Rudik [331]
3 years ago
15

5 The element sulfur is classified as a (1) metal (3) nonmetal (2) metalloid (4) noble gas

Chemistry
2 answers:
Alexxandr [17]3 years ago
7 0
Sulfur is a non-metal, being in the third period, in group 6
blagie [28]3 years ago
6 0
Sulfur is a nonmetal
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How many moles would be equal to 22.4 g of CO2?
Rzqust [24]

Answer:

Number of moles = 0.51 mol

Explanation:

Given data:

Mass of CO₂ = 22.4 g

Number of moles = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Molar mass of CO₂ = 44 g/mol

by putting values,

Number of moles = 22.4 g/ 44 g/mol

Number of moles = 0.51 mol

4 0
3 years ago
An understanding of periodic trends is important because the trends 1. can be used to convert non-useful elements to useful ones
Andreas93 [3]
<span>3. relate to properties of elements and how they may react. Periodic trends are specific patterns that are present in the periodic table that include size, electronic properties, melting point, electronegativity and metallic character. The trends exist due to the similar atomic structure of the elements within each group family.</span>
8 0
3 years ago
3. Methyl acetate is hydrolyzed at 25 oC in acidic environment. Aliquots of equal volume are removed and titrated with NaOH solu
avanturin [10]

Solution :

Time (sec)       Volume of NaOH (mL)

339                           26.23

1242                         27.80

2745                        29.70

4546                         3.81

$\infty$                               39.81

Now the example of the first order kinetics w.r.t volumetric analysis is :

$k=\frac{2.303}{t} \log \left(\frac{v_{\infty}-v_0}{v_{\infty}- v_t}\right)$

Here, $v_{\infty}= \text{ volume at }\infty = 39.81$

$v_{t}= \text{ volume at time 't' } = 27.80$

$v_0$ = volume at time 0 = 0

Since the interval is not constant, we take the time interval as

$=\frac{903+1503+1801}{3}$

$=\frac{4207}{3}$

= 1402.3333

≈  1402 seconds

$k=\frac{2.303}{1402} \log \left(\frac{39.81-0}{39.81-27.80}\right)$

  $=(0.001643) \log \left(\frac{39.81}{10.01}\right)$

  = 0.001643 x 0.52045

  = 0.00082

  $= 8.55 \times 10^{-4} \ sec^{-1}$

Therefore, the first order rate constant is k $= 8.55 \times 10^{-4} \ sec^{-1}$.

5 0
3 years ago
An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0
3 years ago
This for number 8 and 9
3241004551 [841]

Okay for 8 it is the maximum levels will be higher and for 9 is poor circulation leads to lack of nutrients and oxygen

6 0
3 years ago
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