Answer:
σ*2pₓ, also called 
Explanation:
I have drawn the MO diagram for fluorine below.
Each F atom contributes seven valence electrons, so we fill the MOs of fluorine with 14 electrons.
We have filled the 
and 
MOs.
They are the highest occupied molecular orbitals (HOMOs).
The next unfilled level (the LUMO) is the σ*2pₓ orbital. If you use the symmetry notation, it is called the orbital.
This is the orbital that fluorine uses when it acts as an electron acceptor.
Answer:
719.83°C
Explanation:
The heat that the sample of Zinc gives is equal to the heat that water is absorbing. That is:
C(Zn) * m(Zn) * ΔT(Zn) = C(H2O) * m(H2O) * ΔT(H2O)
<em>Where:</em>
<em>C is specific heat (Zn: 0.390J/g°C; H2O: 4.184J/g°C)</em>
<em>m is mass (Zn: 2.50g; H2O: 65.0g)</em>
<em>ΔT (Zn: ?; H2O: (22.5°C - 20.0°C = 2.50°C)</em>
<em />
Replacing:
0.390J/g°C * 2.50g * ΔT(Zn) = 4.184J/g°C * 65.0g * 2.50
ΔT(Zn) = 697.33°C
As final temperature of Zn is 22.50°C, initial temperature is:
Initial temperature: 697.33°C + 22.50°C
719.83°C
<em />
Answer:
Concentration: 0.185M HX
Ka = 9.836x10⁻⁶
pKa = 5.01
Explanation:
A weak acid, HX, reacts with NaOH as follows:
HX + NaOH → NaX + H2O
<em>Where 1 mole of HX reacts with 1 mole of NaOH</em>
To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).
18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX
In 20.0mL = 0.0200L =
0.00370 moles HX / 0.0200L = 0.185M HX
The equilibrium of HX is:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
And Ka is defined as:
Ka = [H⁺] [X⁻] / [HX]
<em>Where [H⁺] = [X⁻] because comes from the same equilibrium</em>
As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M
Replacing:
Ka = [H⁺] [H⁺] / [HX]
Ka = [1.349x10⁻³M]² / [0.185M]
Ka = 9.836x10⁻⁶
pKa = -log Ka
<h3>pKa = 5.01</h3>
I think they can change into ions
Answer:
A medium.
<h3>Explanation:</h3>
It's the material the wave is travelling through.
