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olasank [31]
3 years ago
15

How do we find the acceleration from a velocity vs. time graph

Physics
1 answer:
BabaBlast [244]3 years ago
3 0

The formula for acceleration is A= (V1 - V0) over Time


You might be interested in
A common misconception is that an object always moves when a force acts on it. Why is this statement incorrect? Explain the conc
dsp73

Answer:

The statement is incorrect because, a force acting on an object does not necessarily have to produce motion.

People have the misconception that when a force acts on an object it always produces motion

Explanation:

The statement is incorrect because, a force acting on an object does not necessarily have to produce motion. It could be in static equilibrium where the net force is zero and produces not motion. The body could also be in dynamic equilibrium when  no net force acts on it moving at a constant velocity. But here we are concerned with static equilibrium since the body does not move at all.

People have the misconception that when a force acts on an object it always produces motion and, we have seen from the above tat its not always true.

3 0
3 years ago
Why is it necessary to centrifuge out any precipitate formed in the unknown solution and continue testing the remaining unknown
jonny [76]

Answer:

Precipitation is the formation of a solid from a solution. It is necessary to centrifuge the precipitate to exert sufficient forces of gravity to bring the solid particles in the solution to come together and settle

Explanation:

When you centrifuge precipitate it enables the nucleation to form.

Centrifuging the precipitate helps in determining whether a certain element is present in a solution or not.

5 0
3 years ago
A length of copper wire carries a current of 14 A, uniformly distributed through its cross section. The wire diameter is 2.5 mm,
gavmur [86]

Answer:

a. ρ_\beta=1.996J/m^3

b. U_E=9.445x10^{-15} J/m^3

Explanation:

a. To find the density of magnetic field given use the gauss law and the equation:

i=14A, d=2.5mm, R=3.3Ω, l=1 km, E_o=8.85x10^{-12}F/m, u_o=4*x10^{-7}H/m

ρ_\beta=\frac{\beta^2}{2*u_o}

ρ_\beta=\frac{1}{2*u_o}*(\frac{u_o*i^2}{2\pi *r})^2

ρ_\beta=\frac{u_o*i^2}{8\pi*r}=\frac{4\pi *10^{-7}H/m*(14A)^2}{8\pi*(1.25x10^{-3}m)^2}

ρ_\beta=1.996J/m^3

b. The electric field can be find using the equation:

U_E=\frac{1}{2}*E_o*E^2

E=(\frac{i*R}{l})^2

U_E=\frac{1}{2}*8.85x10^{-12}*(\frac{14A*3.3}{1000m})^2

U_E=9.445x10^{-15} J/m^3

4 0
3 years ago
At which location would you expect the LOWEST TEMPERATURE?
MissTica

Answer:

c

Explanation:

3 0
2 years ago
Read 2 more answers
PLEASE HELP ME!!!! i will give brainliest to whoever gets it right
Oksanka [162]

Answer:

I believe the answer is B.)

6 0
3 years ago
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