In the basic hydrogen atom, shown below left, the cloud is densest in the center and thins out with distance from the nucleus, which means the electron is most likely to be found near the nucleus, in a region about 1/20 nm in size.
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Explanation:
Given that,
Mass of the cart, 
Mass of the cart 2, 
Final speed of cart 2, 
Final speed of cart 1 is 0 as it comes to rest.
Let us assume that the initial velocity of the cart 2 is 0. So using the conservation of linear momentum as :
So, the initial velocity of the 1.0-kg cart is 0.9 m/s.
F = qE = mg
E = mg/q = 0.017*9.81('-3.1x10^-6) = 5.38x10^4 = -53,800 N/C
E' = 0.5E = -26,900N/C
2q -mg= ma, Answer is 9.81 m/s^2 and it's positive because the force is upward.
Answer:
Free-fall is defined as the movement where the only force acting on an object is the gravitational force.
By the second Newton's law, we have that:
F = m*a
Where F = Force, m = mass, a = acceleration.
We can write this as:
a = F/m
And the gravitational force can be written as:
F = (G*M/r^2)*m
Where G is the gravitational constant, M is the mass of the Earth in this case, and r is the distance between both objects (the center of the Earth and the free-falling object)
As the radius of the Earth is really big, the term inside the parentheses is almost constant in the region of interest, then we can write:
G*M/r^2 ≈ g
And the gravitational force is:
F = g*m
And by the second Newton's law we had:
a = F/m = (g*m)/m = g
a = g
Then the acceleration does not depend on the mass of the object.
Then the thing that is common among the free-falling objects is the vertical acceleration.
Answer:
The kinetic energy is 303178 Joule
Explanation:
We must change the speed units to m / s =
1km ---- 1000meters
1h ----- 3600 seconds
v = (95km 1000m / km) / (1h x 3600s / h) = 26, 4 m / s
We use the Kinetic Energy formula: Ec = 1/2 m x v ^ 2
Ec = 1/2 x 870 kg x (26, 4) ^ 2 = 303177, 6 Joule
