Answer:
Explanation: pressure = force / area
Rearrange to get: force = pressure x area. 900 cm2 = 0.09 m2
force = 90 x 0.09
= 8.1 N
Answer:
Height as seen by the professor = 38.2 m
Explanation:
Angle of throw = θ = 69°
Velocity of throw = v
X component of velocity = v₁ = v cos 69 = 0.3584 v m/s
Vertical component of the velocity = v₂ = v sin 69 = 0.9336 v m/s
v₂ / v₁ = tan 69 = 2.605
v₂ = 2.605 v₁.
Professor sees as if the x component of velocity =0
v (as seen by professor) + v' = 0
=> v as seen by professor = -v' = -10.5 m/s
This shows that y component of the ball's velocity is 2.605 times its x component of velocity.
with respect to the professor, there is only y component of velocity.
v₂' =v₂ = 2.605 ( -10.5) = 27.4 m/s.
Height as seen by the professor = (27.4)² / 2(9.8) = 38.2 m
I think the correct answer from the choices listed above is the first option. The one satellite has all the momentum before they connect, and then afterwards they share it. <span>For a collision occurring between object 1 and object 2 in an isolated system, the total </span>momentum<span> of the two objects before the collision is equal to the total </span>momentum<span> of the two objects after the collision.</span>
Answer:
0.26
Explanation:
Given that :
Diameter of ball = 3.81 cm = 3.81/100 = 0.0381 m
Radius (r) = 0.0381 / 2 = 0.01905 m
Average density of ball (Db) = 0.0842 g/cm³ = (0.0842 / 1000)kg / 10^-6 = 0.0842/ 1000 * 10^6 = 84.2kg/m³
Density of water (Dw) = 1000kg/m³
Volume of hollow ball: (4/3) * pi * r³
V = (4/3) * π * 0.01905^3
V = 0.0000289583 m³
Required force = (Dw * V * g) - (Db * V * g)
= (1000 * 0.0000289583 * 9.8) - (84.2 * 0.0000289583 * 9.8)
= 0.259896109172
= 0.2598 N
