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34kurt
3 years ago
5

A common misconception is that an object always moves when a force acts on it. Why is this statement incorrect? Explain the conc

ept correctly. Why do you think some people have this misconception?
Physics
1 answer:
dsp733 years ago
3 0

Answer:

The statement is incorrect because, a force acting on an object does not necessarily have to produce motion.

People have the misconception that when a force acts on an object it always produces motion

Explanation:

The statement is incorrect because, a force acting on an object does not necessarily have to produce motion. It could be in static equilibrium where the net force is zero and produces not motion. The body could also be in dynamic equilibrium when  no net force acts on it moving at a constant velocity. But here we are concerned with static equilibrium since the body does not move at all.

People have the misconception that when a force acts on an object it always produces motion and, we have seen from the above tat its not always true.

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A 720 kg roller-coaster starts off from Location A. Assuming friction does not impede the car's motion, what will be the change
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According to newton, doubling the distance between two interacting objects:
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2 years ago
Which statement is true according to Newton's first law of motion?
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An object in motion tends to stay in motion an oject at rest stays at rest.
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3 years ago
A child of mass 25 kg is skating fast, +10 m/s, and tries to get revenge by colliding with the 60 kg adult who is sitting still.
tankabanditka [31]

Answer: -4.4 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=m_{1}V_{o}+m_{2}U_{o} (2)

p_{f}=m_{1}V_{f}+m_{2}U_{f} (3)

m_{1}=25 kg is the mass of the child

V_{o}=10 m/s is the initial velocity of the child

m_{2}=60 kg is the mass of the adult

U_{o}=0 m/s is the initial velocity of the adult (it is sitting still)

V_{f} is the final velocity of the child

U_{f}=6 m/s is the final velocity of the adult

Substituting (2) and (3) in (1):

m_{1}V_{o}+m_{2}U_{o}=m_{1}V_{f}+m_{2}U_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{o}-m_{2}U_{f}}{m_{1}} (5)

V_{f}=\frac{(25 kg)(10 m/s)-(60 kg)(6 m/s)}{25 kg} (6)

Finally:

V_{f}=-4.4 m/s This means the velocity of the child is in the opposite direction

4 0
3 years ago
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