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34kurt
4 years ago
5

A common misconception is that an object always moves when a force acts on it. Why is this statement incorrect? Explain the conc

ept correctly. Why do you think some people have this misconception?
Physics
1 answer:
dsp734 years ago
3 0

Answer:

The statement is incorrect because, a force acting on an object does not necessarily have to produce motion.

People have the misconception that when a force acts on an object it always produces motion

Explanation:

The statement is incorrect because, a force acting on an object does not necessarily have to produce motion. It could be in static equilibrium where the net force is zero and produces not motion. The body could also be in dynamic equilibrium when  no net force acts on it moving at a constant velocity. But here we are concerned with static equilibrium since the body does not move at all.

People have the misconception that when a force acts on an object it always produces motion and, we have seen from the above tat its not always true.

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Write an equation for the nth term of the arithmetic sequence: 64, 78, 92, 106, ...
Anna [14]

If  64  is term #1 of the sequence,
then the general term is
                                      <em> T(n) = 50 + 14n </em>.


4 0
4 years ago
What is the x-component of a vector with a magnitude of 115 km at an angle of 22°?
ruslelena [56]

The x-component of a vector are < 106.6, 43.07 >

Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.

If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,

v = ||v|| cos θi + ||v|| sin θj

 =  < ||v|| cos θ , ||v|| sin θ >

Magnitude p = 115 km

Angle = 22°

p = ||p|| < cos θ, sin θ >

p = 115 < cos 22°, sin 22° >

p = 115 < 0.927, 0.3746 >

p = < 106.6, 43.07 >

Therefore,  the x-component of a vector are < 106.6, 43.07 >

Learn more about vectors here:

brainly.com/question/8043832

#SPJ1

4 0
2 years ago
The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00 N/C · m) x. Point A is on the y axis at y
igor_vitrenko [27]

Answer:

   V_{b}-V_{a} = -38.72

Explanation:

Consider the axis diagram attached.

Given:

                                        Ey = Ez = 0

                                       Eₓ = - 4x N/C · m

Since electric field is in x direction, potential difference would be:

              V_{b} - V_{a} =-\int\limits^{4.40}_{0} {E_{x} } \, dx

Here we integrate between limits 0 and 4.40 which is distance between A and B along x-axis.  

              V_{b} - V_{a} = -4 \left[\begin{array}{ccc}\frac{x^{2} }{2} \end{array}\right]^{4.40}_{0}

                       V_{b}-V_{a} = -4 (9.68)\\V_{b}-V_{a} = -38.72

5 0
3 years ago
I would like to know the correct answer for this
Mnenie [13.5K]

The last choice on the list is the correct one, for both #2 and #3.

3 0
4 years ago
Convert the following in to SI units without changing its values<br> a. 4000 g <br>b. 2.4 km​
lana66690 [7]

hi <3

i believe i explained this answer properly in my last answer but it would be 4kg and 2400m as these are the SI units for these values.

hope this helps :)

3 0
3 years ago
Read 2 more answers
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