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netineya [11]
3 years ago
13

What is the characteristic that allows an object to have kinetic energy?

Physics
1 answer:
Shtirlitz [24]3 years ago
6 0
Kinetic energy is movement, thus movement would be a characteristic that allows an object to have kinetic energy
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Two parallel slits are illuminated by light composed of two wavelengths. Wavelength A is 564 nm and the other is wavelength B an
anygoal [31]

Answer:

423nm

Explanation:

To find the unknown wavelength you take into account the distance y to the maximum central fringe, for light fringes and dark fringes.

- for light fringes:

dsin\theta=m\lambda\\\\sin\theta\approx\theta=\frac{y}{D}\\\\y=\frac{m\lambda_1D}{d}

- for dark fringes:

y=\frac{m\lambda_2/2 D}{d}

The third-order bright fringe (m= 3) of wavelength A coincides with the fourth dark fringe (m=4) of the wavelength B. Hence you have that:

\frac{(3)\lambda_1D}{d}=\frac{(4)\lambda_2D}{d}\\\\\lambda_2=\frac{3}{4}\lambda_1=\frac{3}{4}(564nm)=423nm

hence, the wavelength B is 423nm

7 0
4 years ago
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TRUE OR FALSE : Boyle’s law states that, as the pressure of a gas increases, the volume decreases.
sveta [45]

At first glance, this statement seems to be true.  But after about a
microsecond of further consideration, one realizes that the statement
would actually set Boyle spinning in his grave, and is false.

Boyle's law states that there is a firm relationship among the pressure,
temperature, and volume of an ideal gas, and that you can't say anything
about how any two of these quantities depend on each other, unless you
also say what's happening to the third one at the same time.

As the pressure of an ideal gas increases, the volume will decrease in
direct proportion to the volume, IF THE TEMPERATURE OF THE GAS
REMAINS CONSTANT.

If you wanted to, you could increase the pressure AND the volume of an
ideal gas both at the same time.  You would just need to warm it enough
while you squeeze it.

8 0
3 years ago
How much time would it take for the sound of thunder to travel 2000 meters of sound travels at the speed of 330 meters per secon
SpyIntel [72]

Time = (distance covered) / (speed)

Time = (2,000 m) / (330 m/s)

<em>Time = 6.06 seconds</em>

5 0
3 years ago
Unlike eukaryotes, prokaryotes do not have:
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D. a membrane bound nucleus , lmk if im right
5 0
3 years ago
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UN ELEVADOR DE TALLER TIENE PISTONES DE ENTRADA Y DE SALIDA , CON DIAMETRO DE 15 cm Y 40 cm RESPECTIVAMENTE, SE USA EL ELEVADOR
Studentka2010 [4]

Answer:

a) La fuerza que se aplica al pistón de entrada tiene una magnitud de 1968.75 newtons.

b) La presión que se aplica al pistón de entrada es de 111408.460 pascales.

Explanation:

a) Este problema se resuelve mediante el Principio de Pascal, el cual establece que la presión dentro de un sistema hidráulico cerrado es la misma en cualquiera de sus puntos. Por tanto, podemos calcular la fuerza aplicada al pistón de entrada mediante la siguiente relación:

\frac{F_{in}}{\frac{\pi}{4}\cdot D_{in}^{2}} = \frac{M\cdot g}{\frac{\pi}{4}\cdot D_{out}^{2} }

F_{in} = \left(\frac{D_{in}}{D_{out}} \right)^{2}\cdot M\cdot g (1)

Where:

F_{in} - Fuerza aplicada al pistón de entrada, en newtons.

D_{in} - Diámetro del pistón de entrada, en metros.

D_{out} - Diámetro del pistón de salida, en metros.

M\cdot g - Peso del carro, en newtons.

Si sabemos que D_{in} = 0.15\,m, D_{out} = 0.40\,m y M\cdot g = 1.4\times 10^{4}\,N, entonces la fuerza aplicada al pistón de entrada es:

F_{in} = \left(\frac{0.15\,m}{0.40\,m} \right)^{2}\cdot (1.4\times 10^{4}\,N)

F_{in} = 1968.75\,N

La fuerza que se aplica al pistón de entrada tiene una magnitud de 1968.75 newtons.

b) Ahora, presión aplicada al pistón de entrada (p), en pascales, queda descrita a través de la siguiente expresión:

p = \frac{F_{in}}{\frac{\pi}{4}\cdot D_{in}^{2} } (2)

Si sabemos que F_{in} = 1968.75\,N y D_{in} = 0.15\,m, entonces la presión aplicada al pistón de entrada es:

p = \frac{1968.75\,N}{\frac{\pi}{4}\cdot (0.15\,m)^{2} }

p = 111408.460\,Pa

La presión que se aplica al pistón de entrada es de 111408.460 pascales.

3 0
3 years ago
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