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swat32
3 years ago
9

molly had a ribbon that was 23 inches long she cut 7 inches off the ribbon how long is her ribbon now

Mathematics
2 answers:
Readme [11.4K]3 years ago
8 0
It’s 16 inches long. 23 - 7 = 16
kodGreya [7K]3 years ago
3 0
If it was originally 23 inches and 7 were cut off she would be left with 16 inches.

23-3 = 20
7-3 = 4
20-4= 16
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If x = 5 and y = x + 1 , find (x+y)+1/2<br> Pls quickly , ill mark branliest
elena-s [515]

Answer:

23/2

Step-by-step explanation:

If x = 5,

y = 5 + 1 = 6

(5+6) + 1/2 = 11 + 1/2 = 23/2

7 0
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Gnoma [55]

The answer is 8 and heres why:

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7 0
3 years ago
Find the area .............​
Natali5045456 [20]

Answer:

Area of the Trapezoid is=  13.5cm^2

Step-by-step explanation:

The given figure is in the shape of a trapezoid:

Area of a trapezoid= (1/2)*(Sum of parallel opposite sides)* (Distance between the parallel sides)

The parallel sides are: 6 cm and 3 cm

Distance between parallel sides= 3 cm

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                    =\frac{1}{2} *(6+3)*3\\\\=\frac{1}{2}*9*3\\\\=\frac{27}{2} \\\\=13.5 cm^2

Area of the Trapezoid is=  13.5cm^2

5 0
3 years ago
Order from least to greatest 1/5 1/2 and 1/3
Sedaia [141]

Step-by-step explanation:

recommended is to convert to decimal

1/5 is 0.2

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5 0
3 years ago
Read 2 more answers
Find the equation of the graphed line.
belka [17]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y =  \dfrac{5}{2}x + 5\bigg) \ is \ correct  }}}

<h3><u>Step-by-step explanation:</u></h3>

Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-

\large\boxed{\orange{\bf y = mx + c} }

We know that slope is \tan\theta. So here slope will be ,

\red{\implies slope = \tan\theta} \\\\\implies slope =\dfrac{PERPENDICULAR}{BASE} \\\\\bf \implies slope =\dfrac{5}{2}

Hence the slope is 5/2 . And here value of c will be 5 since it cuts y axis at (5,0).

\purple{\implies y = mx + c }\\\\\implies y = \dfrac{5}{2}x + 5 \\\\\underline{\boxed{\red{\tt \implies y = \dfrac{5}{2}x + 5 }}}

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>[</u><u> </u><u>d</u><u> </u><u>]</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u><u> </u></h3>
4 0
3 years ago
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