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marta [7]
3 years ago
5

Three points are collinear.

Mathematics
2 answers:
dangina [55]3 years ago
7 0

Answer:

Three points are collinear if they belong to the same line. Also if their Determinant equals zero.

Step-by-step explanation:

Suppose we have A (-6, 2) B(-3,-1) and D(-5, 1). Are they collinear?

Well, let's plug in the values in a Matrix and then calculate its Determinant this way:

Plug ig the values for x, y and complete it with 1 in the 3rd column.

\left[\begin{array}{ccc}x&y&1\\&&1\\&&1\end{array}\right]

Applying:

Det=\left[\begin{array}{ccc}-6&2&1\\-3&-1&1\\-5&1&1\end{array}\right]=0

Doing the calculation, the Determinant equals zero, what gives us an Analytical Geometry proof of its collinearity.

il63 [147K]3 years ago
3 0
If they are in the same line yes. If they aren't then its considered non-collinear.
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Answer: $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.

Step-by-step explanation:

1. Let's call the amount he got paid per hour at his job as a cashier: x.

Let's call the amount he got paid per hour at his job delivering newspapers: y.

2. Keeping on mind the information given in the problem above, you can make the following system of equations:

\left \{ {{5x+4y=77 \atop {6x+3y=78}} \right.

3. You can solve it by applying the Substitution method, as following:

- Solve for one of the variables from one of the equations and substitute it into the other equation to solve for the other variable and calculate its value.

- Substitute the value obtained into one of the original equations to solve for the other variable and calculate its value.

 4. Therefore, you have:

5x+4y=77\\5x=77-4y\\x=\frac{77-4y}{5}=15.4-0.8y

Then:

6(15.4-0.8y)+3y=78\\92.4-4.8y+3=78\\-1.8y=-14.4\\y=8

Finally:

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Therefore he got paid $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.

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