By definition, the sine of an angle is given by:
![sin \alpha = \frac{C.O}{h}](https://tex.z-dn.net/?f=sin%20%5Calpha%20%3D%20%20%5Cfrac%7BC.O%7D%7Bh%7D%20)
Where,
C.O: opposite leg
h: hypotenuse
The hypotenuse is given by:
![h = \sqrt{(61}](https://tex.z-dn.net/?f=h%20%3D%20%20%5Csqrt%7B%2861%7D%20)
So, replacing values we have:
![sin \alpha = \frac{5}{\sqrt{61}}](https://tex.z-dn.net/?f=sin%20%5Calpha%20%3D%20%5Cfrac%7B5%7D%7B%5Csqrt%7B61%7D%7D)
Rewriting we have:
Answer:
the sine value of this function is:
A)5 times square root 61 over 61
Answer:
y= -1/4x+2
Step-by-step explanation:
use the slope formula to get the slope: y2-y1/x2-x1 or 1-2/4-0 subtract to get -1/4 that is the m(slope)*x in y=mx+b now for b it is the point in which x=0 so the first point has x=0 and it's y is 2 so b is 2. put it together to get y=-1/4x+2
Use the identity:-
a^2 + b^2 = (a + b)^2 - 2ab
Plugging in the given values;-
a^2 + b^2 = 6^2 - 2*7 = 36-14 = 22 Answer