Answer:
a 0.5
b 0.4831
c 0.4354 < P < 0.53008
Step-by-step explanation:
Given that :
Probability (P) of a head or a tail when a coin is being tossed or flipped = 1/2 = 0.5
Sample size (n) = 296
Selected sample (X) = 143
a) Given that Emily used a coin toss to select either her right hand or her left hand, what proportion of correct responses would be expected if the touch therapists made random guesses?
The proportion of correct responses that would be expected if the touch therapists made random guesses is 0.5
b) Using Emily's sample results, what is the best point estimate of the therapists' success rate?
Point estimate 
= 
= 0.4831
c) Using Emily's sample results, construct a 90% confidence interval estimate of the proportion of correct responses made by touch therapists.
The 
for 90% is 1.645
Using the formula P" -E < P < P" + E
where E = margin of error : 
= 0.0477
∴ P" -E < P < P" + E
= 0.4831 - 0.0477 < P < 0.4831 + 0.0477
= 0.4354 < P < 0.53008
Answer:
Parenthesis
Exponents
Multiplication and Division
Addition and Subtraction
Hope this helps!
Answer:C
Step-by-step explanation:
The correct answer is c. To carry out this calculation, we begin by describing the sampling distribution of the sample proportion. The sample size is n=50 and the population proportion of teachers who made an apparel purchase is .56. Shape: because np=(50)(.56)=28 and n(1-p)=(50)(.44) are both at least 10, the shape of the sampling distribution of the population proportion is approximately normal. Center: p=.56. Variability: the standard deviation of the sample proportion is approximately .0702. normalcdf(loser: .6, upper: 1000, mean: .56, SD: .0702)=.284.
B) 64, because all these numbers have a difference of 14, and it you keep going, the 10th term will be 64.
The larger one is (-11 + 41)/2 = 15.
The smaller one is (-11 -41)/2 = -26.
_____
For two numbers a and b with sum s and difference d, you can write the equations
Then adding the equations and dividing that sum by 2, you get
You can subtract the second eqution from the first and get a similar result for the smaller number
These are the formulas we used above.
