<span>The equation is e = 300 - 10t. t is greater or equal than 0 and given that e cannot be negative, 300 - 10 t greaetr or equal than 0 => 10 t greater or equal than 300, and t greater or equal than 300/10 = 30. This is the viable points are times from 0 to 10 and elevation from 300 to 0. Some points are (0,300) which is the initial point (when Rory is on the top); (1, 290); (2, 280); (3, 270); (4, 260); (5, 250); (6, 240); (10, 200), (20, 100), (30, 0).</span>
Answer:
Angle C=35 degrees
Step-by-step explanation:
Angle C is an external angle. So, we can use the external angle theorem and get the equation
Angle C= 1/2(100-30)
Angle C=1/2(70)
Angle C=35 degrees
Answer:
Answer:
As x→∞ , f(x)→-∞
As
x→-∞ , f(x)→∞
Step-by-step explanation:
End behavior is determined by the degree of the polynomial and the leading coefficient (LC).
The degree of this polynomial is the greatest exponent, or
3
.
The leading coefficient is the coefficient of the term with the greatest exponent, or
2
.
For polynomials of even degree, the "ends" of the polynomial graph point in the same direction as follows.
Even degree and positive LC:
As x→∞ , f(x)→∞ As x→∞, f(x)→∞
Even degree and negative LC:
As x→−∞ , f(x)→−∞
As
x→∞ , f(x)→−∞
Answer:
(a) 13536.10J
(b) 27072.20J
Step-by-step explanation:
(a) Height of tank (h) = 4 feet = 4/3.2808 = 1.22m
Volume of water in full tank = 4ft×5ft×4ft = 80ft^3
Volume of water in half tank = 1/2 × 80ft^3 = 40ft^3
Density of water = 62.4lb/ft^3
Mass of water = density × volume = 62.4 × 40 = 2496lb = 2496×0.45359kg = 1132.16kg
Work done to empty half of the tank = mgh = 1132.16×9.8×1.22 = 13536.10J
(b) Work done to empty all of the tank = 2 × work done to empty half of the tank= 2 × 13536.10J = 27072.20J
Yes, good job! Since AB and CD are congruent, so are the angles