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Naddika [18.5K]
3 years ago
10

Which equations are equivalent to the expression below ? Check all that apply

Mathematics
1 answer:
noname [10]3 years ago
5 0

The given expression is 4^{3} \times 4^{x}

By using the law of exponent which states that a^{m} \times a^{n} = a^{m+n}

4^{3} \times 4^{x} = 4^{3+x}

We need to find the equivalent expression for the given expression from the given expressions.

1. 4^{3} \times 4^{x} = 4^{3+x}

This expression is equivalent to the given expression.

2. (4 \times x)^{3} = (4x)^{3} = 64x^{3}

This expression is not equivalent to the given expression.

3. 4^{3-x}

This expression is not equivalent to the given expression.

4. 64 \times 4^{x} = (4)^{3} \times 4^{x}=4^{3+x}

This expression is equivalent to the given expression.

5. 4^{3x}

This expression is not equivalent to the given expression.

6. 16^{3x}=(4^{2})^{3x}=4^{6x}

This expression is not equivalent to the given expression.

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What is the measure of angle c​
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Angle C=35 degrees

Step-by-step explanation:

Angle C is an external angle. So, we can use the external angle theorem and get the equation

Angle C= 1/2(100-30)

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Angle C=35 degrees

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State the degree and end behavior of f(x) = 2x3 – 3x – x2 + 1. Explain or show<br> your reasoning
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Answer:

Answer:

As x→∞ , f(x)→-∞

As

x→-∞ , f(x)→∞

Step-by-step explanation:

End behavior is determined by the degree of the polynomial and the leading coefficient (LC).

The degree of this polynomial is the greatest exponent, or

3

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The leading coefficient is the coefficient of the term with the greatest exponent, or

2

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For polynomials of even degree, the "ends" of the polynomial graph point in the same direction as follows.

Even degree and positive LC:

As x→∞ , f(x)→∞ As x→∞, f(x)→∞

Even degree and negative LC:

As x→−∞ , f(x)→−∞

As

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3 years ago
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A rectangular tank with a base 4 feet by 5 feet and a height of 4 feet is full of water. The water weighs 62.4 pounds per cubic
posledela

Answer:

(a) 13536.10J

(b) 27072.20J

Step-by-step explanation:

(a) Height of tank (h) = 4 feet = 4/3.2808 = 1.22m

Volume of water in full tank = 4ft×5ft×4ft = 80ft^3

Volume of water in half tank = 1/2 × 80ft^3 = 40ft^3

Density of water = 62.4lb/ft^3

Mass of water = density × volume = 62.4 × 40 = 2496lb = 2496×0.45359kg = 1132.16kg

Work done to empty half of the tank = mgh = 1132.16×9.8×1.22 = 13536.10J

(b) Work done to empty all of the tank = 2 × work done to empty half of the tank= 2 × 13536.10J = 27072.20J

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