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Yakvenalex [24]
3 years ago
14

A store sold a case of scented candles for $17.85 that had been marked up by 110%. What was the original price?

Mathematics
1 answer:
OleMash [197]3 years ago
8 0
Your original price would have been $16.23

Explaination: 

Take the new markup price and divide it by the percent it was marked up

17.85 / 1.10 = 16.227

1.10 represents 110%

Round your ending number cause there are only two place holders after the decimal for calculating prices. By doing this we change $16.227 to $16.23.
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QUICK, BRAINLIEST FOR 1ST ANSWER. <br><br>14.5 is incorrect!
ra1l [238]
To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by

1/12.5 = 0.08, or 8%

We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
4 0
3 years ago
What's the solution for y+1/2=3/4
creativ13 [48]
\frac{y+1}{2} = \frac{3}{4}

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2*y + 2*1 = 3

2y + 2 = 3

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2y = 1

y = 1 / 2


6 0
3 years ago
Nerisa has 5 pink bow, 1 Blue bow ,and 4 Purple bows in a box. She will Randomly choose 1 bow from the box
4vir4ik [10]
The answer is A. Hope this helps

3 0
3 years ago
Help! If you know this can you tell me how to do it?
aleksandr82 [10.1K]

Answer:

c

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:

[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?

Put everything over the common denominator now:

\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?

Since sin^2(x)+cos^2(x)=1, we will make that substitution:

\frac{1}{sin(x)cos(x)}

We could separate that fraction into 2:

\frac{1}{sin(x)}×\frac{1}{cos(x)}

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Therefore, the simplification is

sec(x)csc(x)

5 0
3 years ago
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