All categories

3 years ago

Solve for 2: 7x + 156° 9x + 184°

Mathematics

1 answer:

Natalija [7]3 years ago

3 0

Answer:

x = -14

Step-by-step explanation:

Simplifying

7x + 156 = 9x + 184

Reorder the terms:

156 + 7x = 9x + 184

Reorder the terms:

156 + 7x = 184 + 9x

Solving

156 + 7x = 184 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.

156 + 7x + -9x = 184 + 9x + -9x

Combine like terms: 7x + -9x = -2x

156 + -2x = 184 + 9x + -9x

Combine like terms: 9x + -9x = 0

156 + -2x = 184 + 0

156 + -2x = 184

Add '-156' to each side of the equation.

156 + -156 + -2x = 184 + -156

Combine like terms: 156 + -156 = 0

0 + -2x = 184 + -156

-2x = 184 + -156

Combine like terms: 184 + -156 = 28

-2x = 28

Divide each side by '-2'.

x = -14

Simplifying

x = -14

You might be interested in

Why is it so expensive to buy organic food

Jet001 [13]

A few reasons are:
1) They contain very little to no chemicals
2) It takes more work to grow, care for, and harvest
3) Majority of farmers produce organic food as a living so it has to be more expensive if they actually want to make a profit

6 0

3 years ago

12x - 84 = 4x + 12. What does X equal?

Vesnalui [34]

Answer:

Step-by-step explanation:

To solve the problem, you have to leave the x alone,

To do so, you have to add 84 on each side

12x = 4x + 96

Then, subtract 4x on each side,

8x = 96

Then divide each side by 8, so

x = 12

Hope it helps!!

Let me know if I'm wrong or you need help on anything else!!

Also, if you're okay with it, can you plz make be brainliest?

8 0

3 years ago

Read 2 more answers

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

$\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]$

The left and right endpoints of the $i$ -th subinterval, respectively, are

$\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8$

$r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8$

for $1\le i\le4$ , and the respective midpoints are

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8$

Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

$T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}$

Midpoint rule

We approximate the area for each subinterval by

$M_i=f(m_i)(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}$

Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial $p_i(x)$ , where

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It so happens that the integral of $p_i(x)$ reduces nicely to the form you're probably more familiar with,

$S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))$

Then the integral is approximately

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}$

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0

3 years ago

Malik buys and sells car parts. He bought two tires for $45.00 each and later sold them for $65.00 each. He bought three rims fo

Alona [7]

The answer is $213 because you subtract the price sold by the price he bought them for and then you add them together (see work)

6 0

3 years ago

Read 2 more answers

Find minor arc in circle Include correct units

masha68 [24]

Answer:

Same thing here Arc DE is also 100 degreese

cause the lines are connected to the center point.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers