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Ganezh [65]
4 years ago
6

PLEASE HELP i don’t want to failllll this time!

Mathematics
1 answer:
Arlecino [84]4 years ago
6 0

Answer:

C. 115°,65°

Step-by-step explanation:

Make the equation for ∠A equal the equation for ∠C: 100+5x=106+3x. You will find x=3. So you plug that into the equations for ∠A and ∠C. And you know that ∠A and ∠C both equal 115°. You repeat these steps for angles B and D and they equal 65°. Ya welcome.

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HELP PLEASE !!! Place each expression under the equivalent expression in the table.
tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

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=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{x^{2}+3x}{(x+3)(4x-5)}

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=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}

=\frac{8x^{2}-10x}{(4x-5)(8x-10)}=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}

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=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}

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=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}

6). \frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}

=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}

4 0
4 years ago
Read 2 more answers
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Step-by-step explanation:

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