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3 years ago

The product of 5 more than Jenny age and 8. use the variable j to represent Jenny age

Mathematics

1 answer:

nikdorinn [45]3 years ago

7 0

(j+5)*8 is what you're looking for. The braces are important.

You could also write as 8j + 40.

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The equation below represents Function A and the graph represents Function B:

Snezhnost [94]

Answer:

Slope of Function B = – Slope of Function A

Step-by-step explanation:

Slope of function A= $-2$

Slope of function B=$\frac{3-1}{3-2}=2$

6 0

3 years ago

Read 2 more answers

You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 2 or getting heads

tino4ka555 [31]

P(2 or H) = P(2) + P(H) - P(2 and H)

What is the probability of getting a 2 P(2)? = 1/6

What is the probability of getting heads P(H)? = 1/2

P(2 and H) is the product of those two events since the events are independent. = 1/6 * 1/2 = 1/12

P(2 or H) = P(2) + P(H) - P(2 and H)

P(2 or H) = 1/6 + 1/2 - 1/12 = 7/12

5 0

3 years ago

The length of the hypotenuse of a right triangle is 14 inches. If the length of one leg is 6 inches, what is the approximate len

Liula [17]

Using the Pythagorean theorem:

6^2 + X^2 = 14^2

36 + x^2 = 196

X^2 = 196-36

x^2 = 160

x = SQRT(160)

x = 4 SQRT(10)
Or as a decimal:
x = 12.65 inches

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3 years ago

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Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Fantom [35]

Answer:

Step-by-step explanation:

3 0

2 years ago

Among 420 randomly selected employees at a company, the mean number of hours of overtime worked per month is 10 hours and the st

kari74 [83]

The margin of error of the random selection is 0.20

The given parameters are:

$n = 420$ --- the sample size

$\sigma = 1.6$ --- the standard deviation

$\bar x = 10$ --- the mean

$\alpha = 99\%$ --- the confidence level.

The margin of error (E) is calculated as follows:

$E = z \times \sqrt{\frac{\sigma^2}{n}}$

So, we have:

$E = z \times \sqrt{\frac{1.6^2}{420}}$

$E = z \times \sqrt{\frac{2.56}{420}}$

The z-value for 99% confidence level is 2.576.

Substitute 2.576 for z

$E = 2.576 \times \sqrt{\frac{2.56}{420}}$

$E = 2.576 \times \sqrt{0.006095}$

Take square roots

$E = 2.576 \times 0.0781$

Multiply

$E = 0.2012$

Approximate

$E = 0.20$

Hence, the margin of error is 0.20