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FromTheMoon [43]
3 years ago
9

Find the area of the irregular shape

Mathematics
2 answers:
Len [333]3 years ago
7 0
If you section off the 3x3 cube, you can find the areas of the now two figures separately and then add their areas together.

A = bh

A = 10(2)
A = 20

A = 3(3)
A = 9

Total A = 20 + 9
Total A = 29

Answer:
29 units²

Alenkasestr [34]3 years ago
7 0
10*2=20 3*3=9 20+9=29
it is 29
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In a rhombus whose side measures 20 and the smaller angle is 38°. Find the length of the larger diagonal, to the nearest tenth.
Lemur [1.5K]

A rhombus diagonals form right angles. The diagonals also cut in half the angles

use cosine: cos38 = \frac{a}{20\\\\}

a = 20cos38

a=15.8

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3 years ago
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Which situation best represents a linear function?
yanalaym [24]

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A

Step-by-step explanation:

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3 years ago
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NeX [460]

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Step-by-step explanation:

3 0
2 years ago
A) Write the sequence of natural numbers which are multiplied by 3 ?
Volgvan

Answer:

a) 3, 6, 9, 12, 15,...,3\cdot n, b) 4, 7, 10, 13, 16,...,3\cdot n +1, c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function f(n) = 3\cdot n, n\in \mathbb{N}. Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function f(n) = 3\cdot n + 1, n\in \mathbb{N}. Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) f(n) = 3\cdot n

\Delta f = f(n+1) -f(n)

\Delta f = 3\cdot (n+1) -3\cdot n

\Delta f = 3

(ii) f(n) = 3\cdot n +1

\Delta f = f(n+1)-f(n)

\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)

\Delta f = 3

Both sequences are arithmetic.

8 0
2 years ago
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