Answer:
![The\:length\:of\:each\:edge\:is\:9](https://tex.z-dn.net/?f=The%5C%3Alength%5C%3Aof%5C%3Aeach%5C%3Aedge%5C%3Ais%5C%3A9)
Step-by-step explanation:
![Volume\:of\:cube:V=a^{3} \:(a\:is\:the\:length\:of\:each\:edge)\\\Leftrightarrow a=\sqrt[3]{V} \Leftrightarrow a=\sqrt[3]{729} =9](https://tex.z-dn.net/?f=Volume%5C%3Aof%5C%3Acube%3AV%3Da%5E%7B3%7D%20%5C%3A%28a%5C%3Ais%5C%3Athe%5C%3Alength%5C%3Aof%5C%3Aeach%5C%3Aedge%29%5C%5C%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7BV%7D%20%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7B729%7D%20%3D9)
Answer:
approx. 3 hours
Step-by-step explanation:
14 newspapers in 20 minutes means he can deliver 42 newspapers an hour.
60/42 = 1.4285 newspapers per minute
131 x 1.4285 = 187.1335 minutes = 3.1188 hours
The best approximation for sqrt 55 would be: B) 7 2/5
Distance of A from cliff = 1500·arctan(30°) ≅ 723.5 ft
distance of B from cliff = 723.5+1000√3 ≅ 2455.6 ft
tanθ = 2455.6/1500 = 1.637
θ = arctan(1.637) ≅ 58.6°
angle of depression = 90-θ ≅ 30°