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Sholpan [36]
3 years ago
14

What are the zeroes of f(x) = x2 - 6x + 8? (4 points) x = -4, 2 x = -4, -2 x = 4, 2 x = 4, -2

Mathematics
1 answer:
labwork [276]3 years ago
3 0
f(x)=x^2-6x+8\\\\the\ zeros:f(x)=0\to x^2-6x+8=0\\\\x^2\underbrace{-4x-2x}_{=-6x}+8=0\\\\x\cdot x-x\cdot4-2\cdot x-2\cdot(-4)=0\\\\x(x-4)-2(x-4)=0\\\\(x-4)(x-2)=0\iff x-4=0\ or\ x-2=0\\\\therefore\\\\\boxed{x=4\ or\ x=2}
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The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

In this problem, considering the situation described in the text, the distribution is given by:

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More can be learned about discrete distributions at brainly.com/question/24855677

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4 years ago
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6 0
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