Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
B. when something is at rest it has balanced forces. And unbalanced when it's moving.<span />
Answer:
first is 20 second is 40 third is 60 and last is 80
Step-by-step explanation:
The first is proportional the second is proportional and the third is not proportional
3 : 3 times 6 is 18, 2 times 9 is 18 and 3 times 3 is 9 plus 9 is 18
