All categories

3 years ago

What is 12/13 times 10/11

Mathematics

2 answers:

vitfil [10]3 years ago

8 0

120/143. 12 x 10 is 120, and 13 x 11 is 143. It is already in simplest form.

Vadim26 [7]3 years ago

6 0

it would be: 12/13 * 10/11

=120 / 143 in fraction form.

=0.839 in decimal form.

You might be interested in

(PLEASE HELP FAST) What does the y-intercept of this relationship represent?

adelina 88 [10]

Answer:what does the graph look like

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which describes how to graph g (x) = RootIndex 3 StartRoot x minus 5 EndRoot + 7 by transforming the parent function?

ratelena [41]

Answer:

$f(x) =\sqrt[3]{x}$

Step-by-step explanation:

Hello!

Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:

$g(x) = \sqrt[3]{x-5}+7$

To have the the parent function, we must find the parent one, let's call it by f(x).

$f(x) =\sqrt[3]{x}$

This function satisfies the Domain of the given one, because the Domain is still $(-\infty, \infty)$ and the range as well.

Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.

4 0

3 years ago

Y-2=4(x+3) what the slope intercept

Kryger [21]

Answer:

Slope intercept form: y = 4x + 14

Slope: 4

Y-intercept: 14

Step-by-step explanation:

y - 2 = 4(x + 3)

Use distributive property

y - 2 = 4x + 12

y - 2 + 2 = 4x + 12 + 2

y - 0 = 4x + 14

y = 4x + 14

3 0

3 years ago

Find the variance of the following data. Round your answer to one decimal place. x 1 2 3 4 5 P(X=x) 0.3 0.2 0.2 0.1 0.2

Reptile [31]

The variance of a distribution is the square of the standard deviation

The variance of the data is 2.2

<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

$E(x) = \sum x* P(x)$

So, we have:

$E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2$

This gives

$E(x) = 2.7$

Next, calculate E(x^2) using:

$E(x^2) = \sum x^2* P(x)$

So, we have:

$E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2$

$E(x^2) = 9.5$

The variance is then calculated as:

$Var(x) = E(x^2) - (E(x))^2$

So, we have:

$Var(x) = 9.5 - 2.7^2$

$Var(x) = 2.21$

Approximate

$Var(x) = 2.2$

Hence, the variance of the data is 2.2