Question

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Answer 1

In this case it is to find the roots of the polynomial.
 We have then:
 2x ^ 2-5x + 1 = 3
 Rewriting:
 2x ^ 2-5x-2 = 0
 Applying resolver we have
 x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
 Substituting values:
 x = (- (- 5) +/- root ((- 5) ^ 2 - 4 (2) (- 2))) / (2 (2))
 x = (- (- 5) +/- root ((25 + 16)) / (2 (2))
 x = (5 +/- root (41))) / (4)
 x = ((5/4) +/- (root (41)) / 4)
 Answer:
 x = ((5/4) +/- (root (41)) / 4)
 (option 4)