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3 years ago

Solve using elimination x-y= 2x+y=-3

Mathematics

1 answer:

Zigmanuir [339]3 years ago

5 0

Your answer would be (.5,-2,5)

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Brian invests £4000 into his bank account.

siniylev [52]

Answer:

14 years

Step-by-step explanation:

£280 is 7% of 4000 so £4000 euro more would be 4000/280 = 14

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2 years ago

Does 1/2+1/8 = to 3/4

AleksAgata [21]

1/2 is 2/4, and so we would need another 1/4 to make it equal to 3/4
1/8 is not equal to 1/4, so 1/2+1/8 does not equal 3/4

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3 years ago

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If logarithm of 5832 be 6, Find thw base?

Lunna [17]

Answer:

3sqrt(2) ................

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2 years ago

Lowest common multiple of 28 and 42

Delicious77 [7]

7 is the lowest common multiple i think

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3 years ago

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Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

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3 years ago

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