First find x:
3x + 41 + x + x-8 + 2 = 100
Simplify :
5x + 35 = 100
Subtract 35 from both sides:
5x = 65
Divide both sides by 5:
X = 13
Total British stamps = x + x-8 = 13 + 13-8 = 18
Probability of being British = 18/100 = 9/50 as a fraction.
Answer:
y= 20 m
x= 15 m
z= 22 degree
Step-by-step explanation:
15+x=30 m
x=30-15
x= 15 m
z-18=40
z= 40-18
z= 22m
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
That is a question about perimeter of rectangle.
The perimeter of a geometric shape is the sum of the value of the all sides.
In a rectangle, the opposite sides are cogruentes (equals). For example, look at picture below. In that rectangle, the sides AB and DC are equals, and the sides AD and BC are equals.
So, the sides of that rectangular table are: 1.52m, 1.52m, 0.75m and 0.75.
Therefore, the perimeter of that rectangle is 
m.
But that is not the final answer because that is the perimeter in meters and the question want the answer in centimeters.
1 meter has 100 centimeter, so we need to multiplicate the perimeter by 100.
Thus, the perimeter of that rectangular table is 
cm.
