Answer:
<5 ~= <1 - Corresponding Angles Theorem
<1 ~= <7 - Alternate Exterior Angles Theorem
<5~= <7 - Vertical Angles Theorem
line l || line m - Transitive Property
Are you sure you've copied down the original problem exactly as given? i38 = 38i can't be simplified. Perhaps you meant i^38, which is a different matter.
Note that i^38 = i^32 * I^4 * I^2.
Note that i^0, i^4, i^8, etc., all equal 1. Therefore,
i^38 = (1)(1)i^2 = 1*(-1) = -1 (answer)
Well, to calculate the area, we would simply do length times width and we would get our area.
Area = Length * Width
Area = 12cm * 4cm
Area = 48cm squared.
So, in conclusion, the area is 48 cm squared.
You do the sum(40) subtracted by 8, the answer from that divided by 2 since Erin's two times younger.
40-8=32
32÷2=16
Then if you want to check it you do the opposite and get the same sum(40) so 16×2=32 and 32+8=40
Sure.
Can you find a number that goes into both terms, 5k and 35 ?
How about 5 ?
(5k - 35) = 5 times (k - 7) .
