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Basile [38]
3 years ago
5

you get paid $8 an hour. you make $35 in tips. you make $167.00 in a week. how many hours did you work. write an equation to the

problem.
Mathematics
2 answers:
gregori [183]3 years ago
4 0

Answer

they worked 16.5 hours that week.

Step-by-step explanation:

You first subtract the tip by the total cost and that gives you $132.00. and from that cost you divide by $8 which they get paid by the hour... and then you get the 16.5 and that means they worked 16.5 hours that week.

Maurinko [17]3 years ago
3 0

Answer:

I belive the equation would be...

Step-by-step explanation:

8x+$35=$167.00

Hope it helps??

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Barbara wants to buy some glittery heart-shaped beads to make friendship bracelets. The beads she wants come in a small pack wit
faust18 [17]

Answer:

The large pack is a better deal!

Step-by-step explanation:

so first we need to figure out how much the individual beads cost.

Small pack: $ 3.60÷90 = 0.04 cents per bead

Large pack: $9.00 ÷ 300 = 0.03 cents per bead

Hope this helps!!

Have a great day!!

8 0
3 years ago
Classify the triangle below explain how you know (20points)
tatyana61 [14]

The triangle is a isosceles because there is two same sides and one different side

4 0
3 years ago
Write an equation for a line perpendicular to y = 2 x + 4 and passing through the point ( − 2 , 3 ) . Express your answer in slo
aleksklad [387]

Answer:

y = -1/2x + 2

Step-by-step explanation:

A perpendicular line will have a opposite reciprocal slope.

Since the line's slope is 2, the perpendicular line will have a slope of -1/2

Plug in the slope and given point into y = mx + b, and solve for b

y = mx + b

3 = -1/2(-2) + b

3 = 1 + b

2 = b

Plug in the slope and b into y = mx + b

y = -1/2x + 2

So, the equation is y = -1/2x + 2

3 0
3 years ago
Uranus has a mass of 8.68 1025 kg and a radius of 2.56 107 m. Assume it is a uniform solid sphere. The distance of Uranus from t
Lelechka [254]

Answer

Given,

Mass of the Uranus, M = 8.68 x 10²⁵ Kg

Radius of Uranus, R = 2.56 x 10⁷ m

Distance of Uranus, D = 2.87 x 10¹² days

a) Rotational Kinetic energy of the Uranus

moment of inertia of the Uranus

  I = \dfrac{2}{5}MR^2

  I = \dfrac{2}{5}\times 8.68\times 10^{25}\times (2.56\times 10^7)^2

         I = 22.75 x 10³⁹ kg.m²

  Angular speed

     \omega = \dfrac{2\pi}{T} = \dfrac{2\pi}{17.3\times 3600}\

    \omega = 1 \times 10^{-4}

 Rotational Kinetic energy

     KE = \dfrac{1}{2}I\omega^2

     KE = \dfrac{1}{2}\times 22.75\times 10^{39}\times (10^{-4})^2

      KE = 11.38\times 10^{31}\ J

b) Rotational Kinetic energy of Uranus in its orbit around sun

moment of inertia of the Uranus

  I = \dfrac{2}{5}MR^2+ Ma^2

  I = 22.75\times 10^{39}+ 8.68\times 10^{25}\times (2.87\times 10^{12})^2

      I = 7.15 x 10⁵⁰ kg.m²

Angular speed

     \omega = \dfrac{2\pi}{T} = \dfrac{2\pi}{3.08\times 10^4\times 3600\times 24}\

    \omega =2.36\times 10^{-9}

 Rotational Kinetic energy

     KE = \dfrac{1}{2}I\omega^2

     KE = \dfrac{1}{2}\times 7.15\times 10^{50}\times (2.36\times 10^{-9})^2

      KE = 1.99\times 10^{33}\ J

6 0
3 years ago
The function f is in the table. identify the function as linear, exponential, or neither
juin [17]
This function is linear. Here is your graph if you needed to graph it.

http://prntscr.com/ie6xuf
6 0
3 years ago
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