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adoni [48]
3 years ago
6

Josie does 9 minutes

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer: Josie starts working out at 3:09

Step-by-step explanation: I found this answer by adding the workout time together.

tino4ka555 [31]3 years ago
6 0

Answer:

3:09

Step-by-step explanation:

First add the total time of the workout

20+9+7=36

then subtract the end time 3:45 with the workout time:

3:45-00:36=3:09

Check work:

3:09+00:36=3:45

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Peyton is going to invest $9,700 and leave it in an account for 16 years. Assuming the interest is compounded continuously, what
Mariulka [41]

Answer: r ≈ 2.3%

Step-by-step explanation:

5 0
2 years ago
Please help on this math question!!!
Andre45 [30]
I think it’s gonna be 6 adults for every 42 students not really sure so sorry if I got it wrong
6 0
1 year ago
a country will produce 3000 missels this year. each of the short range missles costs $200,000 to produce. Each of the medium ran
guapka [62]

Answer:

Step-by-step explanation:

3000/10=300   300=10% of total missiles

300*3=900(30%)   That country (assuming it is Iran) would produce 900 short missiles and 900 medium missiles. 3000-900(2)=3000-1800=1200.

Iran will produce 1200 long range missiles.

For the cost of the missiles,

200,000*900=180,000,000. 300,000*900=270,000,000.

870M-(180M+270M)=870M-450M=420M

420,000,000/1200=350,000.

Long Range Missiles are $350,000 each... got me thinkin bout buying some...

5 0
2 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
Can you help me out
irga5000 [103]
The correct answer is the letter B)
3 0
2 years ago
Read 2 more answers
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