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Fynjy0 [20]
3 years ago
9

By actual division, find the remainder whenthe polynomial 4x^4 - 6x^3 + 6x^2 - 1 is divided by 2x^2 - 3.

Mathematics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

999

Step-by-step explanation:

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Find mL 1 and mL 2. ​
lesantik [10]

Answer:

8. ∠1=118° ∠2=118°

9. ∠1=72° ∠2=108°

10. ∠1=127° ∠2=127°

Step-by-step explanation:

8. In this problem, 118° is corresponding to ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, meaning that together, they equal 180°. So, to get ∠2, you must subtract 118° from 180°

9. In this problem, 72° is same side interior with ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, so you do 180°-72°=  108°

10. In this problem, ∠1 is vertical angles with 127°, making them equal to each other. ∠2 is corresponding with 127°, making them also equal.

5 0
2 years ago
Triangle ABC , m∠A=45° and c = 16, find b.
zmey [24]

Using the cosine function:

\begin{gathered} \cos (\theta)=\frac{_{\text{ }}adjacent}{_{\text{ }}hypotenuse} \\ so\colon \\ \cos (45)=\frac{b}{16} \end{gathered}

Solve for b:

\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}

5 0
1 year ago
What is the length of the apothem, rounded to the nearest inch? recall that in a regular hexagon, the length of the radius is eq
NNADVOKAT [17]

Answer:

Step-by-step explanation:

What is the length of the apothem, rounded to the nearest inch? recall that in a regular hexagon, the length of the radius is equal to the length of each side of the hexagon. 4 in. 5 in. 9 in. 11 in.

8 0
2 years ago
Read 2 more answers
How can you determine if two expressions are equivalent?
Vladimir [108]
Simplify them until they can be simplified no more, then compare both sides. 
7 0
3 years ago
boxes that are 12 inches tall are stacked next to boxes that are 18 inches tall. what is the shortest height as which the two st
olga55 [171]
18 (goes down): 17, 16, 15
12 (goes up): 13, 14, 15

The shortest height at which the two stacks of boxes will be the same height is 15. 

Hope I was able to help!
6 0
3 years ago
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