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Llana [10]
2 years ago
15

Which is a perfect square? O 20 0 21 O 24 O 25

Mathematics
2 answers:
Juliette [100K]2 years ago
7 0

Answer:

25

Step-by-step explanation:

25

(5)² = 25 OR √25 = 5

xz_007 [3.2K]2 years ago
5 0
The answer is 25
5(5)=25
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6) Add or subtract:<br> a) (4x® - 5x + 15) - (11 - 7x - 2x)<br> b)(9x- 6x® - 7x-2) + (10x - 8x + 11)
Marat540 [252]

Answer:

a) (4x® - 5x + 15) - (11 - 7x - 2x)

b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

Step-by-step explanation:

a) (4x® - 5x + 15) - (11 - 7x - 2x)

b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

6 0
3 years ago
Please help thank you
Makovka662 [10]
1)
45x^3+5x
the GCF is 5x because that is a factor of both.
The answer would be 5x(9x^2+1)

2)
u^2-5u+6
factoring is finding what multiplies to the last number to add to the middle number. Those numbers are -3 and -2.
the answer would be (u-3)(u+2)

3)
m^2-49
difference of perfect squares
answer is (m+7)(m-7)

4)
x^5+4x^4+3x^3
GCF is x^3 so it's x^3(x^2+4x+3)
Factor that and it's x^3(x+3)(x+1)
6 0
3 years ago
Find the values of the measures shown when each value in the data set increases by 25. Mean: 109 Median: 104 Mode: 96 Range: 45
Vikki [24]

Answer:

The new values are as follows:

Mean: 134

Median: 129

Mode: 121

Range=45

Standard Deviation=3.6

Step-by-step explanation:

When a k real number is added to all the elements of the dataset, the new measures of center (mean, median, and mode) are simply found by adding the value k to the previous values. Thus

Mean_{new}=Mean_{old}+k

Here Mean_{old} is 109 and k is 25 thus

Mean_{new}=Mean_{old}+k\\Mean_{new}=109+25\\Mean_{new}=134

Similarly

Median_{new}=Median_{old}+k

Here Median_{old} is 104 and k is 25 thus

Median_{new}=Median_{old}+k\\Median_{new}=104+25\\Median_{new}=129

Also

Mode_{new}=Mode_{old}+k

Here Mode_{old} is 96 and k is 25 thus

Mode_{new}=Mode_{old}+k\\Mode_{new}=96+25\\Mode_{new}=121

When a k real number is added to all the elements of the dataset, the new measures of variation (range and standard deviation) remain the same thus.

Range_{new}=Range_{old}\\Range_{new}=45

Similarly

Standard\ Deviation_{new}=Standard\ Deviation_{old}\\Standard\ Deviation_{new}=3.6

So the new values of mean, median, mode, range, and standard deviation are 134, 129, 121, 45, and 3.6 respectively.

4 0
2 years ago
2/3 (a-b) =c, solve for a
Arturiano [62]
\dfrac{2}{3}(a-b)=c\ \ \ \ |\cdot3\\\\2(a-b)=3c\\\\2a-2b=3c\ \ \ \ |+2b\\\\2a=3c+2b\ \ \ \ |:2\\\\\boxed{a=\dfrac{3c+2b}{2}}
6 0
3 years ago
What is the area of this?
Blizzard [7]

Explanation in image provided below.

4 0
2 years ago
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