Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
Answer:
11/15 OR 0.73
Step-by-step explanation:
2/5 ---> 6/15
1/3 ---> 5/15
6/15 + 5/15 = 11/15
OR
2/5 ---> 0.4
1/3 ---> 0.33
0.4 + 0.33 = 0.73
Answer:
The slope is 3.
Step-by-step explanation:
Let's use the slope formula to calculate the slope of this function. Remember, slope equals rise over run, or the difference between y coordinates divided by the difference between x coordinates of 2 points on the graph.
Let's use the last 2 points in the table: (1, 7) and (2, 10)
=
=
The slope of this function is 3!
Hope this helps :) Feel free to ask me any questions!