Name these Alkenes and alkynes using the IUPAC system
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Answer:
Explanation:
We know that
pH +pOH = 14
Given pH = 8.30
⇒ p0H = 14-8.30 = 5.70
Since, we know that
Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know,
Taking antilog both side, we get :
Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :
Hence, this is the required solution.