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krek1111 [17]
3 years ago
8

I need help on this please

Chemistry
1 answer:
Grace [21]3 years ago
4 0
I believe B would be the answer
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Give an example of something that is observable but does not contain matter.<br> Explain.
ale4655 [162]

 The best example I can give that is observable but does not contain matter is:

sunlight or simply light

 

Light does not contain matter because it is a beam of energy or to be specific made up of packet of photons.

<span> </span>

6 0
4 years ago
I’ve been up all night doin chemistry, can someone please give me the answers
m_a_m_a [10]
Here are your answers:

1. MgBr2 + Cl2 = MgCl2 + Br2

Balancing,
Already balanced.

Type of reaction: single displacement


2. Al + Fe2O3 = Al2O3 + Fe

Balancing,
2Al + Fe2O3 = Al2O3 + 2Fe

Type: single displacement reaction


3. AgNO3 + ZnCl2 = AgCl + N2O6Zn

Balancing,
2AgNO3 + ZnCl2 = 2AgCl + N2O6Zn

Type: double displacement reaction

MnO2
4. H2O2 ====== O2 + H20 [being catalyzed by manganese dioxide]

Balancing,
MnO2
2H2O2 ====== O2 + 2H2O

Type: decomposition reaction


5. Zn + HCl = ZnCl2 + H2

Balancing,
Zn + 2HCl = ZnCl2 + H2

Type: single displacement reaction


6. H2SO4 + NaOH = Na2SO4 + H2O

Balancing,
H2SO4 + 2NaOH = Na2SO4 + 2H2O

Type: Acid-base reaction




That took hella long!!! Hope it helps.
4 0
3 years ago
Determine the total pressure of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, , molar mass = 227.10 g/mol) reacts a
bija089 [108]

Answer:

Total pressure is 1189 atm

Explanation:

This is the reaction:

4C₃H₅(NO₃)₃  →  6N₂  +  O₂  +  12CO₂  +  10H₂O

As we have the volume of TNT, we must know the density to find out the mass and then, apply molar mass to calculate mole.

TNT density = 1.654 g/mL

Density = mass / volume

1.654 g/mL = TNT mass / 50mL

1.654 g/mL . 50mL = TNT mass → 82.7 g

Mass / Molar mass = Mol → 82.7 g / 227.1 g/m = 0.364 mole

Now, we can calculate all the mole for the formed gases.

4 mole of TNT produce 6 mole N₂ ___ 1 mol O₂ __ 12 mole dioxide __ 10 mole of water

0.364 mole of TNT will produce:

- (0.364  . 6) /4 = 0.546 mole of produced nitrogen

- (0.364 . 1) /4 =  0.091 mole of produced oxygen

- (0.364 . 12) /4 = 1.092 mole of produced dioxide

- (0.364 . 10) /4 = 0.91 mole of produced vapour of water.

Total mole = 0.564 + 0.091 + 1.092 + 0.91 = 2.657 mole

Let's apply the Ideal Gases Law to find the total pressure, at STP

In STP, pressure is 1 atm for 1 mole at 273K, in a volume of 22.4 mL

But we have a volume of 50mL, and we have 2.657 total mole

Don't forget to convert 50 mL to L, cause the units for R

50 mL = 0.050L

P . 0.050L = 2.657 mol . 0.082L.atm/mol.K . 273K

P = (2.657 mol . 0.082L.atm/mol.K . 273K) / 0.050L

P = 1189 atm

3 0
3 years ago
Calculate the pH for the following buffer solutions with steps.
max2010maxim [7]

Answer:

Answer is shown on the paper :D

Explanation:

Remember to follow sig-figs.

5 0
3 years ago
Which has a higher concentration of water molecules— 200 molecules of water, or a mixture of 300 molecules of water and 100 mole
Dovator [93]
<h3>Answer:</h3>

            200 molecules of water has the highest concentration.

<h3>Explanation:</h3>

                    In chemistry, Concentration is defined as the amount of substance divided by the total volume of the constituents making the mixture.

<u>Case 1:</u> 200 Molecules of Water:

                                                     In this case we are having system which is made up of 200 purely water molecules and there is no other substance present in the system. Hence, for ease we can write it as,

           Concentration  =  Molecules of Water ÷ Total Molecules of Mixture

           Concentration  =  200 ÷ 200

           Concentration  =  1

<u>Case 2:</u> 300 Molecules of Water and 100 Molecules of Food Coloring:

                                                     In this case we are having a mixture which is made up of 300 water molecules and 200 food coloring molecules. Hence, we can write it as,

           Concentration  =  Molecules of Water ÷ Total Molecules of Mixture

           Concentration  =  300 ÷ (300 + 200)

           Concentration  =  300 ÷ 500

           Concentration  =  0.6

Therefore, it is proved that the concentration of pure 200 molecules of water is greater.

7 0
4 years ago
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