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abruzzese [7]
3 years ago
8

You are conducting a weathering study and your solution analysis indicates that you have 1.8 X 10-3 M silica and a pH of 3. You

plug this data into your chemical speciation computer program and indicates that quartz precipitates. Do you think this will happen
Chemistry
1 answer:
Basile [38]3 years ago
3 0

Answer:

I do not think it will happen

Explanation:

The result is not general and can only occur when there is higher temperatures and pressure. Only when there's high temperature and pressure, will the solution precipitate.

More so; kinematically, the result is limited though it can happen in thermodynamics environment.

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Which of these elements is unlikely to form covalent bonds? s, h, mg, ar, si?
kari74 [83]
<span>Answer: K because it is metal and typically forms ionic bonds. Ar is also unlikely to form any bonds because it has a full outer shell of electrons, but it can form covalent bonds.</span>
4 0
3 years ago
Read 2 more answers
A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

6 0
3 years ago
If the edge length of the unit cell is 705.2 pm, what is the density of KI in g/cm3.
Kipish [7]

The density  is 3.144 g / cm^3.

<u>Explanation</u>:

If effective number of atom in NaCl type structure, z = 4

a = 705.2 pm ⇒ In centimeter = 705.2 \times 10^-10

Na = 6.023 \times 10^23

density = (molecular weight) (z) / (Na) (a^3)

where molecular weight of KI is 166 g,

           Z represents the atomic number

density = (molecular weight) (z) / (Na) (a^3)              

             = (166 \times 4) / (6.023 \times 10^23) \times (705.2 \times 10^-10)

density = 3.144 g / cm^3.

5 0
3 years ago
GIVING BRAINLIEST TO WHOEVER HAS THE BEST ANSWERS! :D
Strike441 [17]

Answer:

1. All the possible energy transformations that occur with a dishwasher that uses electrical energy are heat energy because the dishwasher uses the electrical energy to heat the water, also electrical energy is transformed into kinetic energy and sound energy the reasoning behind this is that the parts moving inside the dishwasher is causing the sound.

2. Take as an example a light bulb inside a lamp to illuminate a room. When you plug it in a plug and turn it on, light is generated. More precisely, heat (Joule effect) is produced inside the lamp by its internal filament (conductive material) when it passes through the electrical energy, generated by the friction of the atoms that are inside it when it encounters a resistance.

Explanation:

Hope this helps love!! btw love ur pfp

4 0
2 years ago
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Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 2.60μm2. conve
garri49 [273]
Given that 1 micrometer or micron (um) is equivalent by definition to 1 x 10^-6 m, this means that 1 square micron (um^2) is equivalent to (1 x 10^-6)^2 m^2, or 1 x 10^-12 m^2.

(2.60 um^2) * (1 x 10^-12 m^2 / 1 um^2) = 2.60 x 10^-12 m^2
Therefore the layer of graphene covers an area of 2.60 x 10^-12 m^2.
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5 0
3 years ago
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