If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 
then 
will also be a solution.
Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:
The magnitude of vecor v is given to be 10. So we can write:
Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.
The point in option d, satisfies the equation.
Thus, the answer to this question is option D
Answer:
a)15:6 b)2:3
Step-by-step explanation:
No. of used books=15-9=6
a) 15:6
b)
6:9
2:3
Answer:
-9 + 5 = -4
Step-by-step explanation:
I think that's what your asking.....
Answer:
is wrong，6/20,3/10
Step-by-step explanation:
