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Slav-nsk [51]
3 years ago
11

A certain corporation listed their sales in 100s as 20700. What was their actual volume in millions?

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer: Their actual volume in millions is 207×10⁹.

Step-by-step explanation:

Since we have given that

A certain corporation listed their sales in 100s as 20700

We need to find their actual volume in millions,

According to question,

In 100s, their volume = 2070000

In 100000, their volume is given by

207\times 10^5\\\\=2070000\times 10^5=207\times 10^9

Hence, their actual volume in millions is 207×10⁹.

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What is the next term of the following sequence? <br><br><br> 20, 10, 5, 21/2, ...
ycow [4]

Answer:

1 \frac{1}{4}

Step-by-step explanation:

Note there is a common ratio between consecutive terms, that is

10 ÷ 20 = 5 ÷ 10 = 2 \frac{1}{2} ÷ 5 = \frac{1}{2}

Thus to obtain the next term in the sequence multiply the previous term by \frac{1}{2}

2 \frac{1}{2} × \frac{1}{2} = 1 \frac{1}{4}

6 0
3 years ago
Write the equation of the line that passes through the points (1, -6) and (8, 9). Put
ZanzabumX [31]

Answer:

y-9 = \frac{15}{7} (x-8)

Step-by-step explanation:

Point-slope form is represented by y-y_1 = m (x-x_1). To write an equation with it, we need the slope of the line and a point the line crosses through. We already have at least one point the line crosses through, so let's figure out the slope.

To find the slope, use the slope formula \frac{y_2-y_1}{x_2-x_1}. x_1 and y_1 represent the x and y values of one point the line crosses, and x_2 and y_2 represent the x and y values of another point the line crosses. So, using the x and y values of (1, -6) and (8, 9), substitute them into the formula and solve:

\frac{(9)-(-6)}{(8)-(1)} \\= \frac{9+6}{8-1} \\= \frac{15}{7}

Thus, the slope is \frac{15}{7}.

2) Now, using the point-slope form of  y-y_1 = m (x-x_1),  substitute m, x_1, and y_1 for real values in order to write an equation in point-slope form. The m represents the slope, so substitute \frac{15}{7} in its place. The x_1 and y_1 represent the x and y values of one point on the line. So, choose any one of the points given - either one is fine - and substitute its x and y values for x_1 and y_1. (I chose (8,9)). This gives the following equation and answer:

y-9 = \frac{15}{7} (x-8)

5 0
3 years ago
What formula should be used to find the circumference of a circle
Inessa05 [86]
The circumference = π x the diameter of the circle (Pi multiplied by the diameter of the circle). Simply divide the circumference by π and you will have the length of the diameter. The diameter is just the radius times two, so divide the diameter by two and you will have the radius of the circle
3 0
3 years ago
Read 2 more answers
The given model is a nonlinear function.<br><br> A. True <br> B. False
schepotkina [342]
<h3>Answer: A. True</h3>

=====================================================

Explanation:

Let x be the number of years since 1995. So x = 0 represents 0 years from 1995, x = 1 is 1 year after 1995, and so on.

The first row of the table is (x,y) = (0, 625) with y being the number of salmon.

The second row is (1, 400).

Let's find the slope of the line through these two points.

m = (y2-y1)/(x2-x1)

m = (400 - 625)/(1 - 0)

m = (-225)/1

m = -225

This tells us the salmon population dropped by 225 in the course of a year from 1995 to 1996.

-------------------------------

The third row shows (2, 225). Let's find the slope of the line through the two points (1, 400) and (2, 225)

m = (y2-y1)/(x2-x1)

m = (225 - 400)/(2-1)

m = (-175)/(1)

m = -175

The slope is different from the previous result. Because of this discrepancy, this means we do not have a linear model. The slope should be the same for any two points you pick from this table if you wanted a linear model.

Put another way, there is less steep a drop of the population, and the decay curve is slowly flattening out.

6 0
3 years ago
I really need help please!
irga5000 [103]

Answer:

1. 256 bacteria cells 2. y=2^x 3. 2 bacteria cells

Step-by-step explanation:

7 0
3 years ago
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