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Ksivusya [100]
4 years ago
10

The cost for 4 dinners plus a 20% tip is $24.00. write an equation representing the situation if pp is the price of the dinner i

n dollars. you may asssume there is no tax
Mathematics
1 answer:
jek_recluse [69]4 years ago
6 0
To find the equation, simply write out what the problem states: the cost of 4 dinners plus the cost of 0.2 dinners (20%) is $24.00:

4pp + 0.2pp = 24

Simplify:

4.2pp = 24
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You roll a fair 6 sided die. what is p (roll less than 4)
Darina [25.2K]

Answer:

1/2

Step-by-step explanation:

Since this die has 6 sides, for each roll it has 6 outcomes.

Hence the probability of it landing on any specific number is 1/6.

Since there are only 3 outcomes wanted (roll less than 4 so it can be 1, 2, or 3) then we have to add the probability of each number being rolled so that is:

1/6 chance of rolling1

1/6 chance of rolling2

1/6 chance of rolling3

1/6 + 1/6 + 1/6

=3/6

=1/2

3 0
4 years ago
Which of the following circles have their centers in the second quadrant? Check all that apply.
steposvetlana [31]
<span>B. (x + 1)2 + (y - 7)2 = 16
</span>D. (x + 2)2 + (y - 5)2 = 9
3 0
4 years ago
Use the method of variation of parameters to find a particular solution of the given differential equation. Then check your answ
olga_2 [115]

Answer:

Therefore the complete primitive is

y=c_1 e^{2y}+c_2e^{3t}+e^{t}

Therefore the general solution is

y=c_1e^{2t}+c_2e^{3t}+e^t

Step-by-step explanation:

Given Differential equation is

y''-5y'+6y=2e^t

<h3>Method of variation of parameters:</h3>

Let y=e^{mt} be a trial solution.

y'= me^{mt}

and y''= m^2e^{mt}

Then the auxiliary equation is

m^2e^{mt}-5me^{mt}+6e^{mt}=0

\Rightarrow m^2-5m+6=0

\Rightarrow m^2  -3m -2m +6=0

\Rightarrow m(m  -3) -2(m -3)=0

\Rightarrow  (m-3)(m-2)=0

\Rightarrow  m=2,3

∴The complementary function is C_1e^{2t}+C_2e^{3t}

To find P.I

First we show that e^{2t} and e^{3t} are linearly independent solution.

Let y_1=e^{2t}  and y_2= e^{3t}

The Wronskian of y_1 and y_2 is \left|\begin{array}{cc}y_1&y_2\\y'_1&y'_2\end{array}\right|

                                                =\left|\begin{array}{cc}e^{2t}&e^{3t}\\2e^{2t}&3e^{3t}\end{array}\right|

                                                 =e^{2t}.3e^{3t}-e^{2t}.2e^{3t}

                                                  =e^{5t} ≠ 0

∴y_1 and y_2 are linearly independent.

Let the particular solution is

y_p=v_1(t)e^{2t}+v_2(t)e^{3t}

Then,

Dy_p= 2v_1(t)e^{2t}+v'_1(t)e^{2t}+3v_2(t)e^{3t}+v'_2(t)e^{3t}

Choose v_1(t) and v_2(t) such that

v'_1(t)e^{2t}+v'_2(t)e^{3t}=0 .......(1)

So that

Dy_p= 2v_1(t)e^{2t}+3v_2(t)e^{3t}

D^2y_p= 4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}

Now

4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}-5[2v_1(t)e^{2t}+3v_2(t)e^{3t}] +6[v_1e^{2t}+v_2e^{3t}]=2e^t

\Rightarrow  2v'_1(t)e^{2t}+3v'_2(t)e^{3t}=2e^t .......(2)

Solving (1) and (2) we get

v'_2=2 e^{-2t}    and  v'_1(t)=-2e^{-t}

Hence

v_1(t)=\int (-2e^{-t}) dt=2e^{-t}

and  v_2=\int 2e^{-2t}dt =-e^{-2t}

Therefore y_p=(2e^{-t}) e^{2t}-e^{-2t}.e^{3t}

                     =2e^t-e^t

                    =e^t

Therefore the complete primitive is

y=c_1 e^{2y}+c_2e^{3t}+ e^{t}

<h3>Undermined coefficients:</h3>

∴The complementary function is C_1e^{2t}+C_2e^{3t}

The particular solution is y_p=Ae^t

Then,

Dy_p= Ae^t and D^2y_p=Ae^t

\therefore Ae^t-5Ae^t+6Ae^t=2e^t

\Rightarrow 2Ae^t=2e^t

\Rightarrow A=1

\therefore y_p=e^t

Therefore the general solution is

y=c_1e^{2t}+c_2e^{3t}+e^t

4 0
3 years ago
Write 35/3 as a mixed number.
labwork [276]

Answer:

Answer is 11⅔

Step-by-step explanation:

if want convert improper fraction into mixed number you have divide numerator by denominator

35÷3=11 remainder 2

7 0
3 years ago
On the first day of​ June, there were about 17.71 h of daylight in a city. Five months​ later, there were about 5.30 h of daylig
Andru [333]

Answer:

Percentage increases and decreases, are found by setting the problem up proportionally.

 

You are trying to find what percentage of 17.37 is 8.30 first.

 

so What %/100 = 8.30/17.37

 

Now define a variable:

 

Let x = What%  

 

x/100 = 8.30/17.37

17.37x = 830

x = 830/17.37

x ≈ 47.78

 

8.30 is approximately 47.78% of 17.37, so the percentage decrease is 100% - 47.78% = 52.22%

The percentage decrease is approximately 52.22%

7 0
4 years ago
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