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olga_2 [115]
3 years ago
6

Patrice's credit card has an APR of 11%, calculated on the previous monthly balance, and a minimum payment of 2%, starting the m

onth after the first purchase. Her credit card record for the last 7 months.
How much of the $3900 charge that Patrice made during the first month has been paid off?A. $208.77B. $246.73C. $455.51D. $40.01
Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
3 0
The answer is $246.73 Just for whoever is trying to pass those Apex tests!
Nadya [2.5K]3 years ago
3 0

Answer:

$246.73

Step-by-step explanation:

a.p.e.x

You might be interested in
A school has 300 students.If the ratio of boys to girls is 31 to 44, how many more girls are there in the school?
garri49 [273]

Answer:

there would be 52 more girls I think

Step-by-step explanation:

let x = multiplier then

31x =number of boys

44x = number of girls

Boys + girls = 300

44x + 31x =300

75x = 300

x = 300/75

x = 4 is the multiplier

therefore:

44*4 = 176 girls

31*4 = 124 boys

dif = 52 more girls than boys

hope this helped :)

5 0
2 years ago
Triangle P R Q is shown. Angle R P Q is 39 degrees. The length of P R is 6, the length of R Q is p, and the length of P Q is 8.
KATRIN_1 [288]

According to law of cosines the length of RQ can be written as p^{2} =6^{2} +8^{2} -2*6*8cos(39).

Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.

A length of the triangle can be written as according to law of cosines if sides are given and one angle is a^{2} =b^{2} +c^{2} -2bccos(A)

We have to just put the values in the above equation.

as p^{2} =6^{2} +8^{2} -2*6*8cos(39).

p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.

Hence the side can be written as according to law of cosines if the angle is 39 degrees is  as p^{2} =6^{2} +8^{2} -2*6*8cos(39).

Learn more about trigonometric functions at brainly.com/question/24349828

#SPJ10

7 0
1 year ago
Square ABCD is shown with four congruent images such that ABCD Is congruent to FGHI Is congruent to JKLM Is congruent to NOPQ Is
egoroff_w [7]
JKLM and RSTU transformed figure
5 0
3 years ago
Read 2 more answers
William bought some tickets to see his favorite singer. He bought some adult tickets and some children tickets, for a total of 1
Viefleur [7K]
Hello!

Let 'a' stand for adult tickets and 'c' for children tickets.

a + c = 15

(Both adult and children tickets make up a total of 15 tickets).

30a + 20c = 330

a = 3

c = 12

A N S W E R:

William bought 3 adults tickets and 12 children's tickets.

5 0
3 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
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