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Y_Kistochka [10]
3 years ago
6

Why to astronauts appear weightless while they are filmed performing activities inside the orbiting space shuttle? they are high

enough above the earth's surface that they have escaped the pull of earth's gravity. the space shuttle has anti-gravity devices on it that allow the astronauts to float inside it. the astronauts are falling at the same rate as the space shuttle as it orbits around earth. orbiting objects do not experience any gravity?
Physics
1 answer:
Maslowich3 years ago
7 0

If we see the forces on the astronauts then there is only one force on each astronaut while they are in air.

This force is due to gravity of earth.

Now while the astronauts are in air and doing some activities then the net force on them is counterbalanced on them by centrifugal force.

so we can say the rate of fall of astronauts due to gravity is at same rate as the orbiting rate of the space shuttle.

this is given by

w^2R = g

so all astronauts will experience the situation of free fall.

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Which element of a valid contract is established by getting the signatures of all parties?
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The element of a valid contract which is established by getting the signatures of all parties is <u>mutual agreement</u>

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An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

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2 years ago
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A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling
KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

      \frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}} ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

     \frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} ...... (2)

Now, equating both equations (1) and (2) as follows.

 Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} = Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}        

        \gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}

                    = \frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})

                    = \frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})

                    = 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

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