The time needed to form a soil depends on the latitude: in environments characterized by a mild climate, it takes 200-400 years to form 1 cm of soil. in wet tropical areas soil formation is faster, as it takes200 years. in order to accumulate enough substances to make a soil fertile it takes 3000 years.

Hope it helps! :-)

4 0

4 years ago

A 62.0 kg water skier at rest jumps from the dock into a 775 kg boat at rest on the east side of the dock. If the velocity of th

Dominik [7]

Answer:

v = 0.33 m/s

Explanation:

The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:

$m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f} + m_{2}v_{2f}$

Where:

m1: is the mass of the water skier = 62.0 kg

m2: is the mass of the boat = 775 kg

v1i: is the initial velocity of the water skier = 4.50 m/s

v1f: is the final velocity of the water skier = ?

v2i: is the initial velocity of the boat = 0

v2f: is the final velocity of the boat = ?

Since the final velocity of the skier is the same that the final velocity of the boat, we have:

$m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{f} + m_{2}v_{f}$

$m_{1}v_{1i} + 0 = v_{f}(m_{1} + m_{2})$

$v_{f} = \frac{62.0 kg*4.50 m/s}{(62.0 kg + 775 kg)}$

$v_{f} = 0.33 m/s$

Therefore, the final velocity of the skier and boat is 0.33 m/s.

I hope it helps you!

5 0

4 years ago

A 2.0-kg cart collides with a 1.0-kg cart that is initially at rest on a low-friction track. After the collision, the 1.0-kg car

nikitadnepr [17]

To solve this problem we will apply the concepts related to the conservation of momentum. The momentum can be defined as the product between the mass of the object and its velocity, and the conservation of the momentum as the equality between the change of the initial momentum versus the final momentum. Mathematically, this relationship can be described as

$m_1u_1+m_2u_2 = m_1v_2+m_2v_2$

Here,

$m_{1,2}$ = Mass of each object

$u_{1,2}$ = Initial velocity of each object

$v_{1,2}$ = Final velocity of each object

According to the statement one of the bodies does not have initial velocity, therefore said term would be zero. And the equation could be rewritten as,

$m_1u_1= m_1v_2+m_2v_2$

Replacing the values respectively (The mass of your body with its respective speed we would have)

$2kg(u_1) = 2kg(0.3m/s)+1kg(0.5m/s)$

$u_1 = \frac{2kg(0.3m/s)+1kg(0.5m/s)}{2kg}$

$u_1 = 0.55m/s$

Therefore the initial velocity of the 2kg cart is 0.55m/s

4 0

3 years ago