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3 years ago

11

a rectangular plot of ground is 30 meters longer than it is wide. its area is 15,00 square meters. what equation will help you f

ind the dimensions?

1 answer:

e-lub [12.9K]3 years ago

4 0

Length(width + 30)=15,000 square meters, so the equation is l(w+30)=15,000, either 15,000 or 1,500 i cannot tell which number you were meaning to say because of where your comma is placed.

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12. What's the simplified form of 2x + 3 - X + 5?<br> A. X + 8<br> B. X-2<br> C. X-8<br> D. 3x + 8

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Answer: the answer is a

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3 years ago

What does the line 2x-3y=7 look like

fenix001 [56]

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3 years ago

A) find a cartesian equation for the curve described by the given polar equation. r =3 sin g

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Recall that r^2 = x^2 + y^2, so that r = sqrt(x^2+y^2).

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Squaring both sides,

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3 years ago

Find the lenght of ab

DerKrebs [107]

Answer:

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3 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

3 years ago

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