Based on the calculations, the coordinates of the mid-point of BC are (1, 4).
<h3>How to determine coordinates of the mid-point of BC?</h3>
First of all, we would determine the initial y-coordinate by substituting the value of x into the equation of line that is given:
At the origin x₁ = 0, we have:
y = 2x + 1
y₁ = 2(0) + 1
y₁ = 2 + 1
y₁ = 3.
When x₂ = 2, we have:
y = 2x + 1
y₂ = 2(2) + 1
y₂ = 4 + 1
y₂ = 5.
In order to determine the midpoint of a line segment with two (2) coordinates or endpoints, we would add each point together and divide by two (2).
Midpoint on x-coordinate is given by:
Midpoint = (x₁ + x₂)/2
Midpoint = (0 + 2)/2
Midpoint = 2/2
Midpoint = 1.
Midpoint on y-coordinate is given by:
Midpoint = (y₁ + y₂)/2
Midpoint = (3 + 5)/2
Midpoint = 8/2
Midpoint = 4.
Therefore, the coordinates of the mid-point of BC are (1, 4).
Read more on midpoint here: brainly.com/question/4078053
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Answer:
Step-by-step explanation:
∠WZA + WZY = 180 {linear pair}
88 + ∠WZY = 180
∠WZY = 180 - 88
∠WZY = 92°
∠WXY + ∠WZY = 180 {Opposite angle in cyclic quadrilateral}
x + 92 = 180
x = 180 - 92
x = 88°
parenthesis first -3-11.5
then subtract so your answer is -14.5
The product of the gift and another sum is 1 (27,18)
"<span>9 1/4 ounces of fertilizer, 3/4 ounce of fertilizer for each plant."
Divide the total amt. of fert. by the amt. that goes to each plant:
9 1/4 oz
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(3/4) oz per plant
Convert 9 1/4 to an improper fraction: 9 1/4 = 37/4.
Now divide 37/4 by 3/4, or divide 37 by 3. Result: 12 1/3 plants.
Ms. Marks can fertilize 12 plants and have 1/3 oz of fertilizer left over.</span>
