Answer:
7.5
Step-by-step explanation:
5/6=x/9
cross multiply
6x=45
x=45/6
x=7 3/6 = 7 1/2 = 7.5
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Wouldn’t the answer be 8 and 3
<span>Point A with coordinates (x,y) rotated 180 degrees around O gives point A' with coordinates (-x,-y).
Hope this helps :D
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Divide -3 from both sides leaving you with just m
make sure you switch the inequality sign
