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Talja [164]
3 years ago
9

What can be a visual or mathematical representation of an object?

Chemistry
1 answer:
klio [65]3 years ago
5 0

Answer: Search it up and you will find out

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Glass of orange juice contain 0.90 dL of juice. How many milliliters of orange juice is that?
dlinn [17]
.90 dL is 90 mL because 1 dL is 100 mL
6 0
3 years ago
How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess
Anestetic [448]

Answer:

3.62moles

Explanation:

First let us generate a balanced equation for the reaction

2Na + Cl2 —> 2NaCl

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

From the question,

46g of Na produced 117g of NaCl.

Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl

Converting this mass (211.11g of NaCl) to mole, we obtain:

n = Mass /Molar Mass

n = 211.11/ 58.5

3.62moles

8 0
3 years ago
Why is a molecule of CO2 nonpolar even though the bonds between the carbon atom and the oxygen atoms are polar?
schepotkina [342]
The correct answer is option 1. Carbon dioxide is nonpolar because the shape of the molecule  is symmetrical. It is a linear molecule where the oxygen atoms are symmetrical on each end. CO2 molecule do not have a region of unequal sharing.
7 0
3 years ago
H2 is an example of? A. a molecule B. an element or C. both a molecule and an element.
lesya [120]

Answer:

The answer is both molecule and an element

Hydrogen is the chemical element with the symbol H and atomic number 1. ... At standard conditions hydrogen is a gas of diatomic molecules having the formula H2. It is colorless, odorless, non-toxic, and highly combustible.

Explanation:

7 0
3 years ago
Construct a three-step synthesis of 1,2-epoxycyclopentane from cyclopentanol by dragging the appropriate formulas into the bins.
vladimir2022 [97]

Answer:

(1) Bromination, (2) E2 elimination and (3) epoxidation

Explanation:

  • In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with PBr_{3}
  • In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
  • In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
  • Full reaction scheme has been shown below

8 0
3 years ago
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