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puteri [66]
3 years ago
11

How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess

Chemistry
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

3.62moles

Explanation:

First let us generate a balanced equation for the reaction

2Na + Cl2 —> 2NaCl

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

From the question,

46g of Na produced 117g of NaCl.

Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl

Converting this mass (211.11g of NaCl) to mole, we obtain:

n = Mass /Molar Mass

n = 211.11/ 58.5

3.62moles

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Explanation:

Hello!

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C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)
stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

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For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

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? (x)   :  1

We cross multiply;

3x = 1 * 1

X = 1/3

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What about

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Learn More:

For more on evaluating moles in chemical reactions check out;

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answer:

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A. Atoms only. An element cannot be separated into simpler materials
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