How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess
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Answer:
0.0253 M/s
Explanation:
From the reaction
N₂ + 3H₂ → 2NH₃
The rate of reaction can be written as
Rate = - = -
= +
From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,
So,
Rate of reaction of molecular nitrogen =
Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s