<h2>My a
nswer~</h2>
<em>1253/9997</em> or <em>0.12534</em>
<h3>
My explanation~</h3>
<em>3/4 - 2/6 + 7/24</em>
<em>3/4 </em>= <em>0.75</em>
<em>2/6</em> = <em>0.33</em><em><u>3</u></em>
<em>7/24</em> = <em>0.2916</em><em><u>6</u></em>
<em>0.33</em><em><u>3</u></em> + <em>0.2916</em><em><u>6</u></em> =
<em>0.62466</em>
<em>0.75</em> - <em>0.62466</em> =
<em>0.12534</em>
- then convert back or leave as is
<em>1253/9997</em>
- what you would get when converting back to a fraction
<h2><em><u>hope i helped :P</u></em></h2><h2>
<u><em>---------------------------------------------------------------</em></u></h2>
The required debt-equity ratio is 14:15
<u>Solution:</u>
<em>Given:</em>
Liabilities of the company = $14000
Equity of the company = $15000
<em>To calculate: </em>The debt-equity ratio
Here, the liabilities are included in the debt of the company. The debt-to-equity (D/E) ratio is calculated by dividing a company's total liabilities by its shareholder equity. Therefore, the debt equity ratio is as follows,


The debt-equity ratio reflects the ability of shareholder equity to cover all outstanding debts in the event of a business downturn.
Answer:
x=21 y=58 z=105 have a great day!!!
Step-by-step explanation:
Five voted for green or yellow and 10 voted for red or blue
Answer:
B and C
Step-by-step explanation:
Minimum and Maximum points occur when the gradient of the function is equal to 0. Graphically this looks like a bend such that the function dips from decreasing to increasing (the gradient goes form being negative to positive) and vice versa.
A minimum point occurs where all the nearby values are higher than that of the point in question.
A maximum point occurs where all the nearby points are lower than the point in question.
By looking at the graph, there is a maximum point around (4.5, 1.5) which is consistent with B but not A (since A talks about a minimum point)
By looking at the graph, there is a minimum point around (0.5, 1.5) which is consistent with C.
I've highlighted areas of interest below so hopefully that's helpful :>