The equation of the line represented by the table in slope intercept form is; y = ²/₁₅x + 2
<h3>How to solve equation in slope intercept form?</h3>
The formula for equation of a line in slope intercept form is;
y = mx + c
where;
m is slope
c is y-intercept
The y-intercept will occur when x = 0. Thus, from the table, it is clear hat the y-intercept will be c = 2.
Let us find the slope using the first two points;
m = (2 - 0)/(0 - (-15))
m = 2/15
Thus, the equation is;
y = ²/₁₅x + 2
Read more about Slope Intercept Form at; brainly.com/question/1884491
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8x + 2x
Plug the variable in.
8×6 + 2×6
48+12 = 60
The answer is C Hope this helps!!
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Y=1x -1
this is because you only change the z intercept when lines are parallel
