Which of the following would float in water at 25 ºC?

Chemistry

1 answer:

Sholpan [36]2 years ago

3 0

Answer:

d.A substance with a density of less than 1.00 g/mL.

Explanation:

The density of water, or of any fluid in which you immerse yourself, is directly proportional to the upward force that this fluid will exert on you. That is, the denser the water, the more you can float on it. This is the principle of Archimedes, with his famous Eureka.

In relation to the buoyancy of bodies, it does not depend only on the density of water, or fluid. Buoyancy also depends on the weight / volume of the body being submerged. In this case we are going to focus on the density of water / fluid.

In the case of water in conditions of temperature at 25 ° C the density is usually 1 g / ml so that any object that has a density less than it can float in it.

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Dehydration of 2-methyl-2-pentanol forms one major and one minor organic product. Draw the structures of the two organic product

Korvikt [17]

Answer:

The major product is 2-methyl-2-pentene [ CH₃-CH₂-CH=C(CH₃)₂ ] and a minor product 2-methyl-1-pentene [ CH₃-CH₂-CH₂-C(CH₃)=CH₂ ].

Explanation:

Dehydration reaction is a reaction in which a molecule loses a water molecule in the presence of a dehydrating agent like sulfuric acid (H₂SO₄).

Dehydration reaction of 2-methyl-2-pentanol gives a major product 2-methyl-2-pentene and a minor product 2-methyl-1-pentene.

CH₃-CH₂-CH₂-C(CH₃)₂-OH (2-methyl-2-pentanol)→ CH₃-CH₂-CH=C(CH₃)₂ (2-methyl-2-pentene, major) + CH₃-CH₂-CH₂-C(CH₃)=CH₂ (2-methyl-1-pentene, minor)

Since more substituted alkene is more stable than the less substituted alkene. So, the trisubstituted alkene, 2-methyl-2-pentene is more stable than the disubstituted alkene, 2-methyl-1-pentene.

Therefore, the trisubstituted alkene, 2-methyl-2-pentene is the major product and the disubstituted alkene, 2-methyl-1-pentene is the minor product.

7 0

2 years ago

The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A

Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

$-q_{combust} = q_{water} + q_{calori}$