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3 years ago

Which of the following would float in water at 25 ºC?

Chemistry

1 answer:

Sholpan [36]3 years ago

3 0

Answer:

d.A substance with a density of less than 1.00 g/mL.

Explanation:

The density of water, or of any fluid in which you immerse yourself, is directly proportional to the upward force that this fluid will exert on you. That is, the denser the water, the more you can float on it. This is the principle of Archimedes, with his famous Eureka.

In relation to the buoyancy of bodies, it does not depend only on the density of water, or fluid. Buoyancy also depends on the weight / volume of the body being submerged. In this case we are going to focus on the density of water / fluid.

In the case of water in conditions of temperature at 25 ° C the density is usually 1 g / ml so that any object that has a density less than it can float in it.

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How does the number of coupons you use affect the amount of money you save?

slega [8]

Using coupons seems like an old-fashioned, time-consuming way to save a few cents on the products you buy at the grocery store. After all, most coupons don't usually have a face value of more than $1 and, quite often, they're worth far less. But done properly, couponing can save you thousands of dollars every year.

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3 years ago

The thallium Subscript 81 Superscript 208 Baseline Tl nucleus is radioactive, with a half-life of 3.053 min. At a given instant,

Genrish500 [490]

Answer: (E) 300 bq

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.

Half life is represented by $t_{\frac{1}{2}$

Half life of Thallium-208 = 3.053 min

Thus after 9 minutes , three half lives will be passed, after ist half life, the activity would be reduced to half of original i.e. $\frac{2400}{2}=1200$ , after second half life, the activity would be reduced to half of 1200 i.e. $\frac{1200}{2}=600$ , and after third half life, the activity would be reduced to half of 600 i.e. $\frac{600}{2}=300$ ,

Thus the activity 9 minutes later is 300 bq.

7 0

2 years ago

What volume of oxygen at STP is requieres for the complete combustion of 100.50 mL of C2H2

malfutka [58]

The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

$2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O$

The mole ratio of C2H2 to O2 is 2:5.

1 mole of a gas at STP is 22.4 L.

At STP, 100.50 mL of C2H2 will be:

100.50 x 1/22400 = 0.0045 mole

Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles

0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL

Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

7 0

1 year ago

Question 10 of 25

kap26 [50]

Answer:

Correct option would be A. Mg(s) → Mg2+ + 2e-

Explanation:

Marked as correct answer on Quiz ;) (A P E X)

7 0

2 years ago

Read 2 more answers

Answer the following questions:

Lynna [10]

The relationship of radiation with distance obeys the inverse square law. Therefore, doubling the distance decrease the radiation by a factor of 4. The new count is 250.
1) Applying the same principle, the count decreases by a factor of 100. The new count is 10
2) An alpha particle is 4He2 and the Hydrogen can be represented as 1H1
14N7 + 4He2 - 1H1
= 17X8
Proton number 8 belongs to Oxygen. Therefore, the resultant nucleus is:
17O8
3) 185Au79 - 4He2
= 181Ir77
4) X - 4He2 = 234Th90
X = 238U92
5) Beta emission results in the same nucleon number but an increase in the proton number; therefore, the result is:
234Pa91

7 0

3 years ago