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3 years ago

Which of the following would float in water at 25 ºC?

Chemistry

1 answer:

Sholpan [36]3 years ago

3 0

Answer:

d.A substance with a density of less than 1.00 g/mL.

Explanation:

The density of water, or of any fluid in which you immerse yourself, is directly proportional to the upward force that this fluid will exert on you. That is, the denser the water, the more you can float on it. This is the principle of Archimedes, with his famous Eureka.

In relation to the buoyancy of bodies, it does not depend only on the density of water, or fluid. Buoyancy also depends on the weight / volume of the body being submerged. In this case we are going to focus on the density of water / fluid.

In the case of water in conditions of temperature at 25 ° C the density is usually 1 g / ml so that any object that has a density less than it can float in it.

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To find the formula of a compound composed of iron and carbon monoxide, Fex(CO)y, the compound is burned in pure oxygen, an reac

Anarel [89]

Answer:

The empirical formula is: Fe(CO)₅

Explanation:

According the global reaction:

Feₓ(CO)y + O₂ → Fe₂O₃ + CO₂

You should calculate Fe₂O₃ and CO₂ moles, thus:

0,799 Fe₂O₃ grams × $\frac{1 mole}{159.69 Fe2O3 g}$ = 5,00×10⁻³ Fe₂O₃ moles

2,200 CO₂ grams × $\frac{1 mole}{44,01 CO2 g}$ = 5,00×10⁻²CO₂ moles

The ratio between Fe₂O₃ moles and CO₂ moles is 1:10. Thus ratio between x and y must be 1:5 because Fe₂O₃ has 2 irons but CO₂ has just one carbon.

Assuming the formula is Fe₁(CO)₅ the molecular weight is 195,9 g/mol. Thus:

1,959 Fe(CO)₅ grams × $\frac{1 mole}{195,9 Fe(CO)5 g}$ = 1,00×10⁻² Fe(CO)₅ moles

Thus, assuming 1,00×10⁻² moles as basis for calculation, the global reaction is:

1 Fe(CO)₅ + ¹³/₂O₂ → ¹/₂ Fe₂O₃ + 5 CO₂

With this balanced equation the moles produced have sense, thus, the empirical formula is: Fe(CO)₅

I hope it helps!

8 0

3 years ago

Match each part of the electrochemical cell with its function.

umka21 [38]

Hi!

The correct options would be:

1. Cathode - reduction

The cathode is the negatively charged electrode, and so has an excess of electrons. Cations (positively charged ions) are attracted to the cathode, and gain electrons to acquire a neutral charge. The process in which a gain of electron occurs is called reduction.

2. Anode - oxidation

The opposite occurs at the anode which is positively charged and attracts negatively charged ions, anions. These anions lose their electrons at the anode to acquire a neutral charge, and the process involving loss of electrons is known as oxidation.

3. Salt Bridge - ion transport

Salt bridge is a physical connection between the the anodic and cathodic half cells in an electrochemical cell and is a pathway that facilitates the flow of ions back and forth these half cells. Salt bridge is involved in maintaining a neutral condition in the electrochemical cells, and its absence would result in the accumulation of positive charge in the anodic cell, and negative charge in the cathodic cell.

4. Wire - electron transport

Wires have a universal role of being a pathway for the transport of electrons in circuit. This role is also the same in the wires involved in an electrochemical cells where they are used to transport electrons from the anodic half cell, and this electron transport results in the generation of electricity in the internal circuit of the electrochemical cell.

Hope this helps!

4 0

3 years ago

1. A 1500kg car is being lifted by a hydraulic jack attached to a flat plate. Underneath the plate is

AURORKA [14]

Answer:

the pressure in the pipe in the case when there is no net force on the car is 81,726 N/m^2

Explanation:

a. The computation of the pressure in the pipe in the case when there is no net force on the car is shown below

As we know that

Pressure = F ÷ area

Also

F = mg

Now

= (1500 × 9.8) ÷π (0.24)^2

= 81,726 N/m^2

Hence, the pressure in the pipe in the case when there is no net force on the car is 81,726 N/m^2

5 0

3 years ago

How much heat is required to vaporize 43.9 g of acetone at its boiling point?

bogdanovich [222]

The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below

the heat of vaporization of acetone at its boiling point is 29.1 kj/mole

find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

heat (Q) = moles x heat of vaporization

= 29.1 kj/mole x 0.757 moles = 22.03 kj

5 0

3 years ago

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What do most psychologists believe to be the cause of development?

sattari [20]

b. interaction of nature and nurture

6 0

3 years ago

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