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3 years ago

Which of the following would float in water at 25 ºC?

Chemistry

1 answer:

Sholpan [36]3 years ago

3 0

Answer:

d.A substance with a density of less than 1.00 g/mL.

Explanation:

The density of water, or of any fluid in which you immerse yourself, is directly proportional to the upward force that this fluid will exert on you. That is, the denser the water, the more you can float on it. This is the principle of Archimedes, with his famous Eureka.

In relation to the buoyancy of bodies, it does not depend only on the density of water, or fluid. Buoyancy also depends on the weight / volume of the body being submerged. In this case we are going to focus on the density of water / fluid.

In the case of water in conditions of temperature at 25 ° C the density is usually 1 g / ml so that any object that has a density less than it can float in it.

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What is 2(NH,4)Cr,2 O,7

Vitek1552 [10]

oxidation-reduction.

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3 years ago

The graph shows a relationship between volume and temperature. Which of the following statements is true?

Marat540 [252]

Answer:

The graph shows a directly proportional relationship between volume and temperature and represents Charles' Law.

Explanation:

The relation between volume and temperature is given by :

Ideal gas law, PV = nRT

Where

P is pressure

V is volume

R is gas constant

T is temperature

As volume and temperature have direct relationship. Charles law states that there is a direct relationship between volume and temperature. The correct option is (a).

5 0

3 years ago

A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperatur

garri49 [273]

Heat gained or loss in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1)

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. So, the heat released by the lead is equal to the heat that is absorbed by the water.

</span>Heat = mC(T2-T1) = 50.0 mL (1.00 g/mL) (4.18 J/g °C) (20 °C - 18 °C) = 418 J<span>

</span>

8 0

3 years ago

Read 2 more answers

Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i

swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg

7 0

3 years ago

10: Convert 77.0 L at 18.0 mmHg to its new volume at standard pressure.

olchik [2.2K]

Answer:

The answer to your question is V2 = 1.82 l

Explanation:

Data

Volume 1 = 77 l

Pressure 1 = 18 mmHg

Volume 2 = ?

Pressure 2 = 760 mmHg

Process

Use Boyle's law to solve this problem

P1V1 = P2V2

-Solve for V2

V2 = P1V1/P2

-Substitution

V2 = (18 x 77) / 760

-Simplification

V2 = 1386 / 760

-Result

V2 = 1.82 l

5 0

3 years ago